Two shakes of a lamb's tail.
This equation is based on the Sine function Let w = 2 Pi f The basic V I equation for an inductor is V(t) = L d/dt I(t) Now I(t) = A Sin(w t) V(t) = L d/dt I(t) V(t) = L A w Cos(w t) Z = Vrms / Irms Now Vrms = A L w /Sqrt(2) Irms = A/Sqrt(2) Therefore Z = Vrms / Irms ( A L w /Sqrt(2)) ----------------------- ( A/Sqrt(2) ) Equals L w L 2 Pi f
T = 2*pi*sqrt(L/g) = 2.006 seconds (approx). T = 2*pi*sqrt(L/g) = 2.006 seconds (approx). T = 2*pi*sqrt(L/g) = 2.006 seconds (approx). T = 2*pi*sqrt(L/g) = 2.006 seconds (approx).
The letters X L T
Two little boys had two little toys
In the absolute system, the dimensions of viscosity are (M L^-1 T^-1), surface tension are (M T^-2) and energy are (M L^2 T^-2). In the gravitational system, the dimensions of viscosity are (L^2 T^-1), surface tension are (M L T^-2) and energy are (M L T^-2).
T=2 pi srq (L/g) and omega= (2 pi /T) is simple pendulum Vw = 2 L/T natural speed of walking Fr=V^2 /(gL) Froude number
T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.T = 2*pi*sqrt(l/g) where g is acceleration due to gravity. So T is proportional to sqrt(l).Since both must be positive, the graph of T against L is the shape of the positive square root function.
24 different ways. wow that took a while turkey- TU cheese- C lettuce- L tomato- T Tu, C, L, T Tu, C, T L Tu, L,C,T Tu,L,T,C Tu,C,T,L Tu,C,L,T C,TU,L,T C,TU,T,L C,L,TU,T C,L,T,TU C,T,L,TU C,T,TU,L L,TU,T,C L,TU,C,T L,C,TU,T L,C,T,TU L,T,TU,C L,T,C,TU T,TU,C,L T,TU,L,C T,L,TU,C T,L,C,TU T,C,TU,L T,C,L,TU
When calculating dimensions, you look at the measurement units and ignore the numbers associated with them. Dimensions are represented in square brackets. [L] is a single dimension in length, [T] is time and [M] is mass. [L2] represents length in 2 dimensions - or an area. Slightly more complex are density = [M][L-3] or [M]/[L3] Addition of subtraction can only be carried out on identical dimensions and the result is the same "term". Thus [L2] + [L2] = [L2]. The rules for combination may look strange mathematically, but if you describe the equation in words they may be clear. Add an area to an area and you get and area. Multiplication and division are "normal" and, if you are familiar with indices, they are straightforward. Here is an interesting example of where dimensional analysis can take you. Velocity = [L][T-1] Acceleration = (Change in velocity)/Time = ([L][T-1] - [L][T-1]) / [T] but [X] - [X] = [X] (see rules for addition and subtraction above) = ([L][T-1]) /[T] = [L][T-2] Force = Mass*Acceleration = [M]*[L][T-2] = [M][L][T-2] Energy or mechanical Work = Force*Distance Moved = [M][L][T-2]*[L] = [M][L2][T-2] = [M]*([L][T-1])2 But [L][T-1] is the dimensional representation of velocity So, we have Energy = [M]*velocity2 Or e =mc2 which you may have come across before!
If the force F length l and time T are chosen as fundamental quantities the dimensional formula foe mass
In m l t ml*2 in f l t flt*2
Two shakes of a lamb's tail.