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Sonny Bernhard
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What does 25x divided by 50xy equal in algebra?
It is: 1/2y
What is the answer to 2y² plus y-1?
1
How do you find the solution to x2-4y2 equals 16 and 2y-x equals 2?
x2 - 4y2 = 16∴ (x - 2y)(x + 2y) = 162y - x = 2∴ x = 2y - 2∴ ([2y - 2] - 2y)([2y - 2] + 2y) = 16∴ (y - 1 - y)(y - 1 + y) = 16∴ -1(2y - 1) = 16∴ 1 - 2y = 16∴ -2y = 15∴ y = -7.52y - x = -2∴ -15 - x = -2∴ x = -13So the point of intersection is (-13, -7.5)
What is the answer to 2y plus 8y2?
2y+8y2 can be factored to 2y(1+4y)
What. if its 3y plus 1-2y?
Then 3y+1-2y can be simplified to y+1
How do you write 5 divided by 2y-1 in factor form?
5 x [ 1/(2y-1)] the x is a mult symbol
What does 25x divided by 50xy equal in algebra?
It is: 1/2y
What is 3y divided by 2y?
1.5
Bracket y plus 1close bracket divided by 5 plus bracket 2y plus 1close bracket divided by 2 equals 1 Could anyone help sorry but was not allowed to use punctuation?
(y+1)/5 + (2y+1)/2 = 1 Multiply through by 10 (= hcf of 5 and 2) 2(y+1) + 5(2y+1) = 10 2y+2 + 10y+5 = 10 ie 12y = 3 or y = 1/4
3x y - 2y?
3xy-2y=0 3xy=2y y=2y (3x) y/2y=3x 1/2=3x multiply across by 2 1=6x 1/6=x therefore substituting x=1/6 into 3xy-2y; 3(1/6)y-2y=0 1/2y=2y y=2y/0.5 0.5 aka 1/2 y=1
What is the answer to 2y² plus y-1?
1
What is the sum of 2y plus 1 and y squared plus 1?
(2y + 1) + (y^2 + 1) = 2y + 1 + y^2 + 1 = y^2 + 2y + 2
How do you find the solution to x2-4y2 equals 16 and 2y-x equals 2?
x2 - 4y2 = 16∴ (x - 2y)(x + 2y) = 162y - x = 2∴ x = 2y - 2∴ ([2y - 2] - 2y)([2y - 2] + 2y) = 16∴ (y - 1 - y)(y - 1 + y) = 16∴ -1(2y - 1) = 16∴ 1 - 2y = 16∴ -2y = 15∴ y = -7.52y - x = -2∴ -15 - x = -2∴ x = -13So the point of intersection is (-13, -7.5)
What is 2y-3c?
2y-3c = -1
How do you factor 4x2-4x plus 2xy-2y?
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) (4x + 2y)(x - 1).
What is the answer to 2y plus 8y2?
2y+8y2 can be factored to 2y(1+4y)
How do you use quadratic formula to solve one-third minus 2 divided by 2y plus one equals 3 divided by y?
1/3 - 2/(2y + 1) = 3/y Provided that y ≠-1/2 and y ≠0, multiply through by 3y(2y+1) to give y(2y + 1) - 6y = 9(2y+1) that is, 2y2 + y - 6y = 18y + 9 or 2y2 - 23y - 9 = 0 The quadratic formula then gives y = [23 ± sqrt{232 - 4*2*(-9)}]/(2*2) = [23 ± sqrt(601)]/4 so that y = -0.3788 or y = 11.8788
