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3 Men in a Boat.
Written by Jerome K Jerome in 1889.
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∙ 15y ago
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∙ 15y agothree men in a boat
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How do you factor this problem bt plus 5b-3t-15?
bt + 5b - 3t - 15 = b(t + 5) - 3(t + 5) = (t + 5)(b - 3)
3 B i t E?
3 Bones in the Ear
3 B N S T H R?
I think the question is wrong - it should be 3 B M S H T R The answer is 3 blind mice see how they run.
Which pair of values is the solution to the system of equations below r plus 2t equals -3 and 3r-4t equals -9?
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
What are the release dates for B-J- and the Bear - 1978 S-T-U-N-T- 3-12?
B-J- and the Bear - 1978 S-T-U-N-T- 3-12 was released on: USA: 31 March 1981
John is twice as old as Jane was when he was as old as she is now the sum of their ages is 63 How old are John and Jane?
John is 36, Jane is 27 When he was 27, she was 18. The algebraic solution to the equation: Let A = John and B = Jane, and time t = A - B (difference in ages) If t years ago, John was twice as old A = 2 (B - t) and substitute A - B for t A = 2B - 2A + 2B 3A = 4B A = 4/3 B and since A + B = 63 4/3 B + B = 63 7/3 B = 63 B = 21 and A = 28
What is the answer to this riddle two boys each had a different number of cars Tim said if you give me five ill have as mamy as you and bill said if you give me five ill have twice as many as you?
Using a system of equations where # of Tim's cars = T and # of Bill's cars = B [1] T+5=B-5 [2] 2(T-5)=B+5 Rearrange [1] to get [3] T=B-10 Substitute the latter half of [3] into [2] [4] 2(B-10-5)=B+5 Solve [4] for B 2B-20-10=B+5 B=35 And since [3] B=35 T=25
What are 3 concerns of history?
sh!t b!tches moreon
What are the first and second partial derivates of the redlich-kwong equation of state with respect to V and with constant T?
d2P/dV2 = 2RT(V - b)-3 + a[(2*sqrt(T))*(V2sqrt(T) + Vb*sqrt(T))-2 - 2(V2*sqrt(T) + V*sqrt(T))-3*(2V*sqrt(T) + b*sqrt(T))2]
How many types of Non-Hodgkin Lymphoma are there?
There are at least 10 types of non-Hodgkin's lymphomas.
A father is twelve times as old as his son and the difference in their ages is 40 years. How old is each?
son- b/t 3 and 4 dad- b/t 36 and 48
What does 3 B M S H I R T mean?
3 blind mice see how they run.
