distance travel divided by the time of travel
mass = density * volume weight = mass * acceleration due to gravity W = (2400 kg/m^3)*(1 m^3)*(9.8 m/s^2) = 23520 Newtons convert to pounds 23520 Newtons = 5287.5 lbs (note 1 lb is approximately 4.448 Newtons)
A force vector of -3 Newtons indicates that the force is acting in the opposite direction of the positive direction, with a magnitude of 3 Newtons.
On earth, 3 kg weighs 29.4 newtons. On the moon, the same 3 kg weighs 4.8 newtons. On the way there and back, the same 3 kg weighs zero newtons.
1/6 of 100 newtons is 16 2/3 newtons.
La W was created in 2003-01.
If you convert 3 newtons into kilograms which measure mass you have 0.30591486389338 kg.
W = mg, where W is weight in Newtons, m is mass in kg and g is acceleration due to gravity, 9.8m/s2.W = 5kg x 9.8m/s2 = 49N = 50N rounded to 1 significant figure
It depends on the weight. The work required in joules (kg*m2/s2) is equal to the force applied in newtons and the displacement, or distance, in meters. Thus, for an object that weights 1 N (multiply the weight of the object by the gravitational acceleration, 9.81 m/s2 to transfer to newtons) will require 1 N * 3 m = 3 J. Thus, the formula for work is: W = Fd "W" is the work done on the system. "F" is the force in newtons "d" is the displacement (or distance) of the object in meters.
F =ma where "a" is the accelerationof gravity in m/sec/sec, the weight in Newtons is 9.8 x 3 = 29.4 Newtons
9.8 newtons on earth W= MxG(9.8)
The net force applied downward to the ground is 450 newtons + W newtons. When standing still (not accelerating), the net force must be zero according to Newton's first law. This means the force pushing down must be balanced by the force pushing up (from the ground).
½W - 3 and ½W + 3 (½W - 3) + (½W + 3) = ½W + ½W - 3 + 3 = W |(½W - 3) - (½W + 3)| = |½W - 3 - ½W - 3| = |½W - ½W - 3 - 3| = |-6| = 6 (The difference between two numbers can be calculated by subtracting one from the other and ignoring the sign; |n| is the value of n ignoring the sign.)