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What else can I help you with?
How do you find p(b) when p(a) is 23 p(ba) is 12 and p(a U b) is 45 and is a dependent event?
There are symbols missing from your question which I cam struggling to guess and re-insert. p(a) = 2/3 p(b ??? a) = 1/2 p(a ∪ b) = 4/5 p(b) = ? Why use the set notation of Union on the third given probability whereas the second probability has something missing but the "sets" are in the other order, and the order wouldn't matter in sets. There are two possibilities: 1) The second probability is: p(b ∩ a) = p(a ∩ b) = 1/2 → p(a) + p(b) = p(a ∪ b) + p(a ∩ b) → p(b) = p(a ∪ b) + p(a ∩ b) - p(a) = 4/5 + 1/2 - 2/3 = 24/30 + 15/30 - 20/30 = 19/30 2) The second and third probabilities are probabilities of "given that", ie: p(b|a) = 1/2 p(a|b) = 4/5 → Use Bayes theorem: p(b)p(a|b) = p(a)p(b|a) → p(b) = (p(a)p(b|a))/p(a|b) = (2/3 × 1/2) / (4/5) = 2/3 × 1/2 × 5/4 = 5/12
What is the probability of drawing a ten or a heart?
Let A= drawing a ten B= drawing a heart P(A or B) = P(A) + P(B) - P(A & B) A & B denotes a ten of hearts. P( ten or a heart)= 4/52 + 13/52 -1/52 =16/52 = 4/13
What is the probability of drawing a queen or a club from a deck of cards?
Probability (P) of A or B is: P(A) + P(B) - P(A and B). Apply to the question is: P(Q) + P(Club) - P (Q&Club) = 4/52 + 13/52 - 1/52 = 16/52 = 4/13 or .3077 or 30.77%.
What is the ditloid 4 P B?
7
What is the probability of drawing either a 3 or a heart from a regular bridge deck of cards?
The probability of A is denoted P(A) and the probability of B is denoted P(B). P(A or B) = P(A) + P(B) - P(A and B). Say P(A) = Probability of drawing a heart, which is 13/52. Say P(B) = Probability of drawing a three, which is 4/52. We now have to determine P(A and B) which is the probability of a heart and a three, which is 1/52. We now can determine the probability of drawing a heart or a three which is 13/52 + 4/52 - 1/52 = 16/52 = 4/13.
10 p in g?
4 l on a c = 4 legs on a chair, 4 f on b b is 4 faces on big ben------- so what is 10 p in g
4 and 20 b b b in a P?
Black birds baked in a pie.
Three men are seeking job candidate a and b are given about the same chance of winning but c is given the chance twice as either a or b what is the probability that candidate a doesn't win?
P(A)+P(B)+P(C) = 1 so P(A)+P(A)+2*P(A) = 1 => P(A) = 1/4 and therefore, P(A') = 1 - P(A) = 3/4
What dies 4 and t b b in a p stand for?
4 and twenty blackbirds baked in a pie.
If A and B are independent events then are A and B' independent?
if P(A)>0 then P(B'|A)=1-P(B|A) so P(A intersect B')=P(A)P(B'|A)=P(A)[1-P(B|A)] =P(A)[1-P(B)] =P(A)P(B') the definition of independent events is if P(A intersect B')=P(A)P(B') that is the proof
What is 2 equals P for a T B?
4
What is the product rule and the sum rule of probability?
Sum Rule: P(A) = \sum_{B} P(A,B) Product Rule: P(A , B) = P(A) P(B|A) or P(A, B)=P(B) P(A|B) [P(A|B) means probability of A given that B has occurred] P(A, B) = P(A) P(B) , if A and B are independent events.
