54 cards in a pack with Jokers
54 cards in a deck (with the jokers)
54 cards in a deck with the joker
Example of a popular word and number game. 54 C in the D with J? Can be decoded as 54 Cards in the Deck with Jokers.
54 cards in a deck with jokers.
53 Cards in the Deck with the Joker (1)54 Cards in the Deck with the Jokers (2)
52 Cards in a Deck, not counting the Jokers
cards in a deck (with the jokers)
12 signs of the Zodiac 54 cards in a deck with the Joker
Sorry to delete the previous version of this program, but this one is much more concise and sophisticated. I have written this program for a 3*3 matrix, but if you want to change it, just enter additional variables to store the order of the matrix and then replace the "3"s of the program with them as needed. It's easy. So here we go:#include#includevoid swap(int *x,int *y);main(){int i,j,k,m,n;int matrix[3][3];printf("Enter the matrix: \n\n");for (i=0;i
/* multiplication of a 3*3 matrix*/ #include<stdio.h> main() { int a[3][3],b[3][3],c[3][3]; int i,j,k; printf("enter the elements in A matrix:\n"); for(i=0;i<=2;i++) { for(j=0;j<=2;j++) { scanf("%d",&a[i][j]); } } printf("enter b matrix:\n"); for(i=0;i<=2;i++) { for(j=0;j<=2;j++) { scanf("%d",&b[i][j]); } } for(i=0;i<=2;i++) { printf("\n"); for(j=0;j<=2;j++) { c[i][j]=0; for(k=0;k<=2;k++) { c[i][j] = c[i][j]+a[i][k] * b[k][j]; } } } printf("multiplication matrix is:\n"); for(i=0;i<=2;i++) { for(j=0;j<=2;j++) { printf("%d\t",c[i][j]); } printf("\n"); } }
Two Jokers in a deck of cards.
#includevoid f1(int a[]);int a1[2][2],a2[2][2];int i,j;void main(){for(i=0;i