3root(6)+5root(2) you really answered it yourself!
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
4√5 + 4√5 = 8√5.
5 radical 2 (5√2)
No. In the order of operations, 5 divided by 5 comes first. Let's say x equals 2. 2 plus 5 divided by 5 plus two 2 plus 1 plus 2 3 plus 2 equals 5. The answer is 5
-2 √5 + 3 √5 = (-2 + 3) √5 = 1 √5 = √5
2 radical 2
2 times radical 5 or about 4.472135955
1rad5 + 2rad5 = 3rad5 3 radical 5
2 radical 30
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
76
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
3root(6)+5root(2) you really answered it yourself!
The trick here is to multiply by the value 1, but express it as (5 - √5)/(5 - √5). This forms a difference of squares on the bottom, eliminating the radical:(1 + √5) / (5 + √5)= (1 + √5)(5 - √5) / (5 + √5)(5 - √5)= (5 - √5 + 5√5 - 5) / (25 - 5√5 + 5√5 - 5)= 4√5 / 20= √5 / 5
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
4√5 + 4√5 = 8√5.