CuSO4.5H2O is hydrated copper sulphate ; a COMPOUND, not an element.
However, it comntains the elements ;-
1 x Cu = 1 Copper
1 x S = 1 x Sulphur
4 x O =- 4 x Oxygen
5 X 2 = 10 x H = 10 Hydrogens
5 x 1 = 5 = 5 Oxygens.
So hydrated copper sulphate comtains the elements , copper, sulphur, oxygen , hydrogen , and oxygen (water).
for ahyndrous it is CuS04 for hydrated its CuS04 - 5h20
Copper sulfur oxygen
Well, honey, to find the molar mass of CuSO4·5H2O, you add up the atomic masses of copper (Cu), sulfur (S), oxygen (O), and hydrogen (H), and then multiply by the number of atoms of each element in the compound. So, 0.50 mol of CuSO4·5H2O would have a mass of approximately 249.5 grams. Hope that satisfies your curiosity, darling.
The compound Cu4SO4 5H20 is called copper(II) sulfate pentahydrate.
To balance the equation CuSO4 + Na, follow these steps: Write down the unbalanced equation: CuSO4 + Na → ? Determine the products of the reaction based on the elements involved: CuSO4 + Na → Cu + Na2SO4 Now, balance the equation by ensuring that the number of atoms for each element is the same on both sides: CuSO4 + 2Na → Cu + Na2SO4
cuso4 +5h20 as h2so4 is acting as a dehydrating agent drawing the water out of the cuso4
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
The chemical equation for hydrated copper sulfate is CuSO4 • 5H2O. This indicates that each copper sulfate molecule is associated with 5 water molecules in its crystal structure. When heated, these water molecules are driven off, leaving anhydrous copper sulfate (CuSO4).
for ahyndrous it is CuS04 for hydrated its CuS04 - 5h20
CuCO3 --> CO2 + CuO (gas + black powder) Further heating may result in : CuO --> 2Cu + O2 (metal copper + gas)
Copper sulfur oxygen
The structural formula of CuSO4·5H2O is Cu(H2O)4SO4, where the copper ion (Cu) is surrounded by four water molecules (H2O) and one sulfate ion (SO4). The "·5H2O" indicates that there are five water molecules associated with each formula unit of CuSO4.
Well, honey, to find the molar mass of CuSO4·5H2O, you add up the atomic masses of copper (Cu), sulfur (S), oxygen (O), and hydrogen (H), and then multiply by the number of atoms of each element in the compound. So, 0.50 mol of CuSO4·5H2O would have a mass of approximately 249.5 grams. Hope that satisfies your curiosity, darling.
CuSO4 isn't an element.
The compound Cu4SO4 5H20 is called copper(II) sulfate pentahydrate.
A more reactive element displace the less reactive element from a compound.Example: Fe + CuSO4 = Cu + FeSO4
They fit the pattern: element + compound --> different element + different compound. Example: Zn + CuSO4 --> Cu + ZnSO4.