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Well, honey, to find the molar mass of CuSO4·5H2O, you add up the atomic masses of copper (Cu), sulfur (S), oxygen (O), and hydrogen (H), and then multiply by the number of atoms of each element in the compound. So, 0.50 mol of CuSO4·5H2O would have a mass of approximately 249.5 grams. Hope that satisfies your curiosity, darling.
What else can I help you with?
What is the molar mass of CuSo4 x 5H2O?
The molar mass of CuSO4 x 5H2O (copper (II) sulfate pentahydrate) is calculated by adding the molar mass of CuSO4 (159.61 g/mol) to five times the molar mass of water (5 * 18.02 g/mol). Therefore, the molar mass of CuSO4 x 5H2O is 249.72 g/mol.
How many grams are there in 3 moles of CuSO4?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
What is the mass of CuSO4?
The molar mass of CuSO4 is 159.61 g/mol. To find the mass of a specific amount of CuSO4, you would need to know the number of moles or the mass in grams.
Find the percentage of water to the nearest tenth in crystal of CuSo4 x 5H2O?
The atomic mass of CuSO4 is 159.61 g/mol, and that of 5 H2O is 90.08 g/mol. To find the percentage of water, we calculate (90.08 g/mol / (90.08 g/mol + 159.61 g/mol)) * 100, which is approximately 36.1%. So, the crystal contains around 36.1% water to the nearest tenth.
How many grams would 3.36 1023 molecules of copper (II) sulfate (CuSO4) weigh?
To calculate the weight of 3.36 x 10^23 molecules of CuSO4, you would first find the molar mass of CuSO4 (159.61 g/mol). Then, you'd use this molar mass to convert the number of molecules to grams using the formula: grams = (molecules x molar mass) / Avogadro's number. This would give you the weight of 3.36 x 10^23 molecules of CuSO4.
What is the molar mass of CuSo4 x 5H2O?
The molar mass of CuSO4 x 5H2O (copper (II) sulfate pentahydrate) is calculated by adding the molar mass of CuSO4 (159.61 g/mol) to five times the molar mass of water (5 * 18.02 g/mol). Therefore, the molar mass of CuSO4 x 5H2O is 249.72 g/mol.
What is the percent by mass of sulfur in CuSO4?
The molar mass of CuSO4 is 159.61 g/mol. The molar mass of sulfur (S) is 32.06 g/mol. To find the percent by mass of sulfur in CuSO4, we calculate: (32.06 g/mol / 159.61 g/mol) x 100% = 20.07%. Therefore, sulfur makes up about 20.07% of the mass of CuSO4.
What is the mass of 7050 mol of uranium?
The mass of 7 050 moles of natural uranium is 238,02891 x 7 050.
What is the mass of 1 mole of cuso4?
159.6086g
How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
How many grams are there in 3 moles of CuSO4?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
How will you convert the masses of anhydrous CuSO4 and water to moles?
To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
How many moles are in 44.78 g of cupric sulfate?
CuSO4 (cupric sulfate) has a molecular weight of 159.602g/mol Cu=63.546 S =32.06 O = 15.999 x 4 =63.996 Add the atomic weights of the elements in cupric sulfate. This is 159.602 grams/mol. Now divide the number of grams( 44.78) by the molecular weight of cupric sulfate (159.602). 44.78 g CuSO4/159.602 g/mol CuSO4= .2805 mol(moles) of cupric sulfate. The answer is 0.2805
What is the mass of CuSO4?
The molar mass of CuSO4 is 159.61 g/mol. To find the mass of a specific amount of CuSO4, you would need to know the number of moles or the mass in grams.
How many mol of Aluminum are required to react completely with 1 mol of CuSO4?
2Al (s) + 3CuSO4(aq) ==> Al2(SO4)3 + 3Cu ... balanced equation1 mol CuSO4 x 2 mol Al/3 mole CuSO4 = 0.67 moles Al required.
Find the percentage of water to the nearest tenth in crystal of CuSo4 x 5H2O?
The atomic mass of CuSO4 is 159.61 g/mol, and that of 5 H2O is 90.08 g/mol. To find the percentage of water, we calculate (90.08 g/mol / (90.08 g/mol + 159.61 g/mol)) * 100, which is approximately 36.1%. So, the crystal contains around 36.1% water to the nearest tenth.
How many grams of ammonia are presented in 5.0 l of a 0.050 m solution?
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
