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The CuSO4 molecule is made up of six atoms, one copper, one sulfur and four oxygen. The total mass of the six atoms is 159.609 grams per mole.

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Is the percent by mass of copper in CuSO4  5H2O the same as in CuSO4?

No, the percent by mass of copper in CuSO4  5H2O will be different than in CuSO4 because CuSO4  5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4  5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4  5H2O compared to CuSO4.


What mass of anhydrous copper 2 sulfate can be obtained by heating 125g of cuper 2 sulfate pentahydrate?

To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.


What is the value of x if mass of CuSO4.xH2O and mass of CuSO4 is given after heated?

The value of x can be determined by comparing the masses of CuSO4.xH2O and CuSO4 before and after heating. By calculating the difference in mass, the value of x can be obtained based on the loss of water molecules during the heating process.


How many grams are there in 3 moles of CuSO4?

The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.


What is the molar mass of CuSo4 x 5H2O?

The molar mass of CuSO4 x 5H2O (copper (II) sulfate pentahydrate) is calculated by adding the molar mass of CuSO4 (159.61 g/mol) to five times the molar mass of water (5 * 18.02 g/mol). Therefore, the molar mass of CuSO4 x 5H2O is 249.72 g/mol.

Related Questions

Is the percent by mass of copper in CuSO4  5H2O the same as in CuSO4?

No, the percent by mass of copper in CuSO4  5H2O will be different than in CuSO4 because CuSO4  5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4  5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4  5H2O compared to CuSO4.


What mass of anhydrous copper 2 sulfate can be obtained by heating 125g of cuper 2 sulfate pentahydrate?

To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.


What is the value of x if mass of CuSO4.xH2O and mass of CuSO4 is given after heated?

The value of x can be determined by comparing the masses of CuSO4.xH2O and CuSO4 before and after heating. By calculating the difference in mass, the value of x can be obtained based on the loss of water molecules during the heating process.


How many grams are there in 3 moles of CuSO4?

The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.


What is the percent by mass of sulfur in CuSO4?

The molar mass of CuSO4 is 159.61 g/mol. The molar mass of sulfur (S) is 32.06 g/mol. To find the percent by mass of sulfur in CuSO4, we calculate: (32.06 g/mol / 159.61 g/mol) x 100% = 20.07%. Therefore, sulfur makes up about 20.07% of the mass of CuSO4.


What is the molar mass of CuSo4 x 5H2O?

The molar mass of CuSO4 x 5H2O (copper (II) sulfate pentahydrate) is calculated by adding the molar mass of CuSO4 (159.61 g/mol) to five times the molar mass of water (5 * 18.02 g/mol). Therefore, the molar mass of CuSO4 x 5H2O is 249.72 g/mol.


What is the mass of 0.50 mol of CuSO4 5H20?

Well, honey, to find the molar mass of CuSO4·5H2O, you add up the atomic masses of copper (Cu), sulfur (S), oxygen (O), and hydrogen (H), and then multiply by the number of atoms of each element in the compound. So, 0.50 mol of CuSO4·5H2O would have a mass of approximately 249.5 grams. Hope that satisfies your curiosity, darling.


How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?

29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O


What is the mass of 1 mole of cuso4?

159.6086g


How many moles are in 44.78 g of cupric sulfate?

CuSO4 (cupric sulfate) has a molecular weight of 159.602g/mol Cu=63.546 S =32.06 O = 15.999 x 4 =63.996 Add the atomic weights of the elements in cupric sulfate. This is 159.602 grams/mol. Now divide the number of grams( 44.78) by the molecular weight of cupric sulfate (159.602). 44.78 g CuSO4/159.602 g/mol CuSO4= .2805 mol(moles) of cupric sulfate. The answer is 0.2805


How many grams would 3.36 1023 molecules of copper (II) sulfate (CuSO4) weigh?

To calculate the weight of 3.36 x 10^23 molecules of CuSO4, you would first find the molar mass of CuSO4 (159.61 g/mol). Then, you'd use this molar mass to convert the number of molecules to grams using the formula: grams = (molecules x molar mass) / Avogadro's number. This would give you the weight of 3.36 x 10^23 molecules of CuSO4.


What is the weight in grams of 3.36 1023 molecules of copper sulfate?

What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?