The CuSO4 molecule is made up of six atoms, one copper, one sulfur and four oxygen. The total mass of the six atoms is 159.609 grams per mole.
It's neutral
No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
5
The mass of this answer is 125 g
The mass in grams of 3,20 moles of copper is 158,865 g.
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
5
The mass of this answer is 125 g
159.6086g
The anhydrous copper sulfate (CuSO4) has a molar mass of 159,62.
The mass in grams of 3,20 moles of copper is 158,865 g.
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
Molar mass of CuSO4= 63.5 + 32 +4 x 16=63.5 + 96= 159.5g
You can answer this question using a molar mass calculation for CuSO4. 63.55 g Cu + 32.06 g S + 4(16.00 g O) = 159.55 g CuSO4 In 159.55 g CuSO4, there are 63.55 g Cu. Use this as a conversion factor. 100 g CuSO4 x 63.55 g Cu = 39.8 g Cu .................... 159.55 g CuSO4
Dehydrated copper sulfate contains approximately 12.8% sulfur by weight.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.