No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.
You can answer this question using a molar mass calculation for CuSO4. 63.55 g Cu + 32.06 g S + 4(16.00 g O) = 159.55 g CuSO4 In 159.55 g CuSO4, there are 63.55 g Cu. Use this as a conversion factor. 100 g CuSO4 x 63.55 g Cu = 39.8 g Cu .................... 159.55 g CuSO4
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
Hydrated copper sulfate, CuSO4·5H2O, contains 36.10% water by mass.
The molar mass of CuSO4 is 159.61 g/mol. To find the mass of a specific amount of CuSO4, you would need to know the number of moles or the mass in grams.
The molar mass of CuSO4 is 159.61 g/mol. The molar mass of sulfur (S) is 32.06 g/mol. To find the percent by mass of sulfur in CuSO4, we calculate: (32.06 g/mol / 159.61 g/mol) x 100% = 20.07%. Therefore, sulfur makes up about 20.07% of the mass of CuSO4.
To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.
You can answer this question using a molar mass calculation for CuSO4. 63.55 g Cu + 32.06 g S + 4(16.00 g O) = 159.55 g CuSO4 In 159.55 g CuSO4, there are 63.55 g Cu. Use this as a conversion factor. 100 g CuSO4 x 63.55 g Cu = 39.8 g Cu .................... 159.55 g CuSO4
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
Hydrated copper sulfate, CuSO4·5H2O, contains 36.10% water by mass.
The molar mass of CuSO4 is 159.61 g/mol. To find the mass of a specific amount of CuSO4, you would need to know the number of moles or the mass in grams.
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
The anhydrous copper sulfate (CuSO4) has a molar mass of 159,62.
The formula mass of copper (II) sulfate, CuSO4, is calculated by adding the atomic masses of copper (Cu), sulfur (S), and four oxygen atoms (O) in the compound. The atomic masses are approximately: Cu = 63.5, S = 32.1, O = 16. The formula mass of CuSO4 is 63.5 + 32.1 + 4(16) = 159.5 grams/mole.
The molar mass of CuSO4 x 5H2O (copper (II) sulfate pentahydrate) is calculated by adding the molar mass of CuSO4 (159.61 g/mol) to five times the molar mass of water (5 * 18.02 g/mol). Therefore, the molar mass of CuSO4 x 5H2O is 249.72 g/mol.
To get the molar mass of copper sulfate (CuSO4) Add the molar masses (atomic weight) of each element of the compound together, this will give you the molar mass of the compound. In This case 159.6086 g/mol