First, it's ClO3 with a lowercase L.
There are two possible compounds: copper I chlorate, CuClO3 or copper II chlorate Cu(ClO3)2
Cu(I), cuprous, Cu+.
Positive copper.
This is cobalt(III) chlorate.
single replacement
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
copper (II) chlorate
Cu+
Cu(I), cuprous, Cu+.
mg + CuCl2 + MgCl2 + Cu Mg + Cu^+2 = Mg^+2 + Cu
oxidation
Cu and ZnCl2 are being produced.
Chlorate(V) ion
Chlorate(V) ion
CuSO4 Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O
Cu+ named Cu(I) ion, cuprous ... (in salt names, eg. cuprous oxide, Cu2O)
looks like a single displacement reaction. Cu + AgSO4 Thank you very much!
cu(II) + 2agcl --> 2ag+cucl2