We must remember that pH is defined as the -log[H+]. Therefore, 7.22=-log[H+]. By algebraic rearrangement, we get:
-7.22=log[H+]
10-7.22=[H+]
6.03x10-8=[H+]
We can check our answer by plugging it into the equation for pH.
-log(6.03x10-8)=pH=7.22
pH is defined as -log[H+]. This means that if one knows the concentration of hydrogen ion in solution, the pH is simply the negative logarithm (base 10) of that. Similarly, one can find the pOH simply by substituting the concentration of OH- for the concentration of H+ in the aforementioned formula.
if the pH is 4.7, the H+ concentration is 2 x 10-5
The pH is the co-logarithm of the activity of the dissolved ions H+ in a solution. The formula is (a is the activity):pH = - log10 aH
pH = -log10[H+] = -log10(0.001 mol/L )= -log10(10-3)= 3
The difference between a pH of 7 and a pH of 8 are as follows:A pH of 7 means the concentration of [H+] is 10-7.A pH of 8 means the concentration of [H+] is 10-8.Therefore, a substance with a pH of 8 has 1/10th the concentration of hydrogen ions that a substance with a pH of 7.
Hydrochloric acid is HCl. It is a H plus (H^+) donor, and so adding it to water will INCREASE the H^+ concentration. Increasing the H^+ concentration results in a DECREASE in pH.
When the pH drops from 7 to 5 the H plus concentration increases by 100 times. ie:for every drop back of pH by 1 unit the H plus concentration increases by 10 times.
pH
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
When pH value is decreased 1.0 unit, the H+ concentration is tenfolded, because -log(10.[H+]) = pH + 1.0
As the concentration of H+ increases, the value of pH decreases simultaneously.
pH is defined as -log[H+]. This means that if one knows the concentration of hydrogen ion in solution, the pH is simply the negative logarithm (base 10) of that. Similarly, one can find the pOH simply by substituting the concentration of OH- for the concentration of H+ in the aforementioned formula.
its pH 2 ---> pH 1
pH= -log[H+] pH + pOH = 14 pOH = 14 - pH pOH= -log[OH], so the antilog of -pOH will give you the OH concentration.
if the pH is 4.7, the H+ concentration is 2 x 10-5
The concentration of H+ [H+] = 0.01 m/l by definition pH = -(log10 (0.01)) therefore pH = 2
The pH is the co-logarithm of the activity of the dissolved ions H+ in a solution. The formula is (a is the activity):pH = - log10 aH