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2NH3 is the product of N2+3H2
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
2NH3 + 2NA = 3H2 + NA3N2
h20 , hcn
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
keq = 1.125
keq = 1.125
Given N2(g) + 3H2(g) <---> 2NH3(g), increasing the pressure will cause more NH3 to form. According to LeChatelier's Principle, an increase in pressure moves the equilibrium in the direction where there are fewer moles (particles), which in this equilibrium, is to the right.
N2 + 3H2 --> 2NH3 is possible according to Dalton's theory. It also is probable and is the equation for the Haber process which is used to produce ammonia from nitrogen and hydrogen. You can read about the Haber process by referring to the related link below, if you are interested.
2NH3 is the product of N2+3H2
There weren't any answer choices provided. But I found an example and if this is the example N2(g) plus 3H2(g) equals 2NH3(g) then the answer is none of the above. The question is messed up and all of the answer choices are the same.
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
2NH3 + 2NA = 3H2 + NA3N2
h20 , hcn
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
21 L