0
Grade 316 is the standard molybdenum-bearing grade, second in importance to 304 amongst theaustenitic stainless steels. The molybdenum gives 316 better overall corrosion resistant properties than Grade 304, particularly higher resistance to pitting and crevice corrosion in chloride environments.
Grade 316L, the low carbon version of 316, is immune from sensitisation (grain boundary carbide precipitation). Thus it is extensively used in heavy gauge welded components (over about 6mm). There is commonly no appreciable price difference between 316 and 316L stainless steel.
The austenitic structure also gives these grades excellent toughness, even down to cryogenic temperatures.
Compared to chromium-nickel austenitic stainless steels, 316L stainless steel offers higher creep, stress to rupture and tensile strength at elevated temperatures.
EnduraMet(R) 316LN stainless is a nitrogen-strengthened version of Type 316L stainless. By means of solid solution strengthening, the nitrogen provides significantly higher yield and tensile strength as annealed than Type 316L without adversely affecting ductility, corrosion resistance or non-magnetic properties. In the hot rolled unannealed condition, yield strength of 75 ksi (518 MPa) or higher can be achieved for bar diameters up to 1.375in (34.925mm).
The foregoing information was gathered from two different web locations arrived at by searching for "stainless steel rebar" and "316LN stainless steel."
It appears that Type 316 is a standard stainless steel, 316L is a low carbon stainless steel, and 316LN is a low carbon nitrogen strengthened stainless steel.
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
What is Efficiency of Binary Search tree operations?
If it is an unbalanced binary tree, O( ln( n ) / ln( 2 ) ) is best-case. Worst case is O( n ). If it is balanced, worst case is O( ln( n ) / ln( 2 ) ).
What is the integral of 1 over x?
ln |x|+C is the answer
What is the difference between write and writeln in pascal?
'ln' -- it means 'new line' after writing
Write a c program to find the product of two numbers without using operator?
#include<stdio.h> #include<conio.h> void main() { int a,b,multi; clrscr(); printf("enter a value for a and b"); scanf("%d%d",&a,&b); multi=a*b; printf("the result is %d", multi); getch() }
How do you calculate coefficient of linear expansion of copper?
dL/dT = αL*L, where L is the length of the steel, T is temperature, and αL is the linear thermal expansion coefficient which for steel is about 11.0 to 13.0. That is possibly the easiest differential equation in history: (1/L)dL = (αL)dT ln(L) = αLT L = eαLT
What is the anti derivative of 1 over x?
The anti-derivative of 1/x is ln|x| + C, where ln refers to logarithm of x to the base e and |x| refers to the absolute value of x, and C is a constant.
How would you solve ln 4 plus 3 ln x equals 5 ln 2?
Ln 4 + 3Ln x = 5Ln 2 Ln 4 + Ln x3= Ln 25 = Ln 32 Ln x3= Ln 32 - Ln 4 = Ln (32/4) = Ln 8= Ln 2
How do you work out Ln 24 - ln x equals ln 6?
18
Why is the symbol for natural log ln?
ln(ln)
What is the value of log -2?
[ln(2) + i*pi]/ln(10) if you are referring to log as a base 10 log. ln refers to thenatural logarithm (log base e)The log of any negative number is imaginary. The formula above is derived fromthe relationship:-1 = ei*pisince you want log of -2, multiply both sides by 2-2 = 2*ei*pitaking natural logarithm of both sides: ln( -2) = ln(2*ei*pi ) = ln(2) + ln(ei*pi )which reduces to ln(2) + i*piIf you want log10 then divide both sides by ln(10)So log10(-2) = ln(-2)/ln(10) = [[ln(2) + i*pi]/ln(10)x = log (-2) = log10(-2)10x = -2Think about the smallest possible number you can put in for x.10-∞ = ?10-∞ = 1/10∞10∞ = ∞1/∞ = ?1/∞ = 0It is impossible to ever get 0 or a negative number because you will never reach infinity.log(-2) is undefined
If you have a number with the exponent x how do you find the answer?
Take the natural logarithm (ln) of both sides of the equation to cancel the exponent (e). For example, ify=Aexlog transform both sides and apply the rules of logarithms:ln(y)=ln(Aex)ln(y)=ln(A)+ln(ex)ln(y)=ln(A)+xrearrange in terms of x:x=ln(y)-ln(A), or more simplyx=ln(y/A)
What is the derivative of y equals xlnx?
Use the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln xUse the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln xUse the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln xUse the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
What is equivalent to ln 6 plus ln 4?
You can also write this as ln(6 times 4)
Solve or x 2 ln 9 plus 2 ln 5 equals 2 ln x minus 3?
2 ln(9) + 2 ln(5) = 2 ln(x) - 3ln(81) + ln(25) = ln(x2) - 37.61332 = ln(x2) - 3ln(x2) = 10.61332ln(x) = 5.30666x = e5.30666 = 201.676 (rounded)
How do you solve for x 3 ln x - ln 3x equals 0?
3 ln(x) = ln(3x)ln(x3) = ln(3x)x3 = 3xx2 = 3x = sqrt(3)x = 1.732 (rounded)
Simplify In e to the 7th power?
It depends. If you mean (ln e)7, then the answer is 1, since (ln e) = 1. If you mean ln(e7), then the answer is 7, since ln(e7) = 7 (ln e) and (ln e) = 1.
Is there a function where the first derivative goes to infinity for x going to 0 and where the first derivative equals 0 when x is 1?
Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.
