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pu = p0 + u(p1 - p0)
Addresses 80 - 87H are assigned to the P0 port
If the patient is still pregnant, a patient who is G1 and P0 is a primigravida.
#include<reg51.h> sbit RS=P2^0; sbit E=P2^1; void cmddiply() { RS=0; E=1; E=0; } void datadiply() { RS=1; E=1; E=0; } void delay() { int i; for(i=0;i<30000;i++); } void main() { while(1) { P0=0x38; cmddiply(); delay(); P0=0x0E; cmddiply(); delay(); P0=0x06; cmddiply(); delay(); P0=0x01; cmddiply(); delay(); P0=0x80; cmddiply(); delay(); P0='1'; datadiply(); delay(); P0='7'; datadiply(); delay(); } }
((Q1-Q0)/average of Q0 and Q1) over ((P1-P0)/average of P0 and P1)
The aneroid measures elevation and air pressure has an airtight chamber that is sensetive to changes in the air pressures. Hope this helps.
When the temperature increases, the barrier potential in a semiconductor diode decreases. This is due to the increase in carrier density at higher temperatures, which results in more charge carriers being available to pass through the barrier. Ultimately, this leads to a lower resistance across the diode and a decrease in the potential barrier.
barrier potential P0=(kT/q)*ln(Na*Nd/Ni^2) when T ↑, P0↑.
Coupling efficiency = NA2 such that if you have an initial power output P0 you get P=P0*NA2
The answer depends on the units for 253. 253 metres or 253 kilometres or 253 light years - each will give a different answer.
The loudness of a shout or sound pressure level is found by this form: ptotal = p0 + posc ..where... p0 = local ambient pressure posc = sound pressure deviation