mixture of lead, carbon, oxygen and hydrogen at the ratio of 1, 2, 3, 2. i think???
Lead (II) Acetate
You will get Pb(OH)4
I think you mean Lead (IV) Bicarbonate, which is Pb(HCO3)4
O=-2 Pb=x x+(-2)*2=0 x+4-=0 -4+4=0 Pb4-
Pb
C2+
The reaction is:2 Pb(NO3)2 = 2 PbO + 4 NO2 + O2
Tin and Lead are both metals with oxidation numbers of 2+ and 4+, so the two equations for Lead (Pb) are 2Pb + O2 ---> 2PbO and Pb + O2 ---> PbO2 The equations for Tin (Sn) look the same ... just substitute Sn where you see Pb.
You will get Pb(OH)4
The chemical formula of lead acetate is Pb(CH3COO)4.
Lead (IV) acetate is best written: Pb(CH3COO)4 though occasionally it is seen Pb(C2H3O2)4.
Pb(OH)4 Hydroxide ion has a charge of -1. Since the lead has a charge of +4, you need four hydroxide ions to keep the compound stable
Pb+4 Cl-1
+4 for Pb and -1 for each hydrogen
2 HCl + Pb --> PbCl2 + H2 (for Pb 2+) 4 HCl + Pb --> PbCl4 + 2 H2 (for Pb 4+)
The charge of the Pb ion can be either +2 or +3.
Pb which is neutral has 82 electrons. Thus, if it has a 4+ charge, then it has 78 electrons.
I think you mean Lead (IV) Bicarbonate, which is Pb(HCO3)4