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The change in entropy between products and reactants in a reaction.
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What is t in the equation gh-t s?
In the equation ( gh - t = s ), the variable ( t ) represents a quantity that, when subtracted from the product of ( g ) and ( h ), results in ( s ). To isolate ( t ), you can rearrange the equation to ( t = gh - s ). This means ( t ) is the difference between the product ( gh ) and ( s ).
Who sent messages in a balloon in the civil war?
nobody because they thought it was a piece of S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T
What is h in equation g h -t s?
The change in entropy between products and reactants in a reaction.
What is T in the equation G H - T S?
The change in entropy between products and reactants in a reaction.
What is the T in the equation g h-t s?
The change in entropy between products and reactants in a reaction.
What could make Delta become negative at a given enthalpy and entropy?
The equation for ∆G is ∆G = ∆H - T∆S H is enthalpy and S is entropySo, ∆G is negative if T∆S is greater than ∆H
What is S in the equation G H T S?
The change in entropy between products and reactants in a reaction.
How can photosynthesis be written as an equation?
Well the equation is: 6CO2 + 6H2O + -s-u-n-l-i-g-h-t--> C6H12O6 + 6O2.
What is delta S in the equation delta G delta H-T delta S?
Delta S represents the change in entropy of a system. In the equation delta G = delta H - T delta S, it is used to determine the contribution of entropy to the overall change in Gibbs free energy. A negative delta S value suggests a decrease in the disorder of a system.
What is delta S in the equation delta G delta H - T delta S?
The change in enthalpy between products and reactants in a reaction
An object dropped from a height h attain a velocity of 6m/s just before hitting the ground, find the value of h?
The equation to calculate the height h is as follows: h = (1/2) * g * t^2 + v0 * t Where g is the gravitational acceleration (9.8 m/s^2), t is the time for the object to fall, and v0 is the initial velocity of the object (0 m/s). So, we can rearrange the equation to solve for t: t = (-v0 + sqrt(v0^2 + 2 * g * h)) / g Substituting in the values given, we get: t = (-0 + sqrt(0^2 + 2 * 9.8 * h)) / 9.8 t = sqrt(2 * 9.8 * h) / 9.8 Now, we know that the object's final velocity is 6 m/s. So, we can use the equation: v = v0 + g * t Where v is the final velocity and v0 is the initial velocity (0 m/s). Substituting in the values given, we get: 6 = 0 + 9.8 * t 6 = 9.8 * t t = 6 / 9.8 Now, we can substitute this value of t back into the original equation to solve for h: h = (1/2) * 9.8 * (6 / 9.8)^2 + 0 * (6/ 9.8) h = (1/2) * 9.8 * 36 / 96 + 0 h = 18 / 48 h = 0.375 m
What is the equation for projectile motion?
h(t)= -g*t^2 + V*t +h where h(t) is the periodic time, t is the overall time, V is the initial velocity, h is the initial hieght, and g is the gravitational constant either 16 or 4.9. This equation will trace the path taken by a projected object.
