It makes specialty beer
cos it did
We use the dot product cos and in vector we use the vector product sin because of the trigonometric triangle.
cos evans plaice is lush but
Because in dot product we take projection fashion and that is why we used cos and similar in cross product we used sin
mterial or product matching the criterial of the certificate of suitability of customer is cos grade
no cos its wrong and dirty
Like normal expansion of brackets, along with: cos(A + B) = cos A cos B - sin A sin B sin(A + B) = sin A cos B + cos A sin B 5(cos 20 + i sin 20) × 8(cos 15 + i sin 15) = 5×8 × (cos 20 + i sin 20)(cos 15 + i sin 15) = 40(cos 20 cos 15 + i sin 15 cos 20 + i cos 15 sin 20 + i² sin 20 sin 15) = 40(cos 20 cos 15 - sin 20 cos 15 + i(sin 15 cos 20 + cos 15 sin 20)) = 40(cos(20 +15) + i sin(15 + 20)) = 40(cos 35 + i sin 35)
L{cos(at)} = s/(s2 + a2)
AnswerIt equals the same thing because in math, a product of two or more trig functions are written as that, just expresed as a product or operation, if is a product of two different functions nothing can be done. But here is the simplest answer:sin x * cos x = 1/2 sin 2x
what is the relationship between marginal physical product and marginal cos
csc[]tan[] = sec[]. L: Change csc[] into one over sin[]. Change tan[] into sin[] over cos[]. R: Change sec[] into one over cos[]. 1/sin[] times sin[]/cos[] = 1/cos[]. L: To multiply 2 fractions, multiply the numerators, and multiply the denominators, and put the numerators' product over the denominators' product. R: Nothing more to do. sin[]/sin[]cos[] = 1/cos[]. L: You have a sin[] on both top and bottom. Cross them off to get a one on the top. 1/cos[] = 1/cos[]. Done. [] is theta. L is the left side of the equation. R is the right side.
Normally you use sine theta with the cross product and cos theta with the vector product, so that the cross product of parallel vectors is zero while the dot product of vectors at right angles is zero.