it means you send it out to everybody that is in your contact list
why do you text in a work sheet
each work is discussed separately.
To calculate the work done by a 1 kW motor in one minute, we can use the formula: [ \text{Work} = \text{Power} \times \text{Time} ] Given that power is 1 kW (or 1000 watts) and time is 1 minute (or 60 seconds), we can substitute the values: [ \text{Work} = 1000 , \text{W} \times 60 , \text{s} = 60000 , \text{J} ] Thus, a 1 kW motor does 60,000 joules of work in one minute.
What area codes work for text now on fire tablets
To find the time it takes for a 500 W electric motor to do (1.50 \times 10^5) J of work, we can use the formula: [ \text{Power} = \frac{\text{Work}}{\text{Time}}. ] Rearranging gives us: [ \text{Time} = \frac{\text{Work}}{\text{Power}} = \frac{1.50 \times 10^5 \text{ J}}{500 \text{ W}} = 300 \text{ seconds}. ] Thus, it would take 300 seconds, or 5 minutes, for the motor to perform that amount of work.
It means that the text is too short to be able to work and/or fit.
a text area is the area where we write our text. and a workspace is the place where we can work anything.
a text area is the area where we write our text. and a workspace is the place where we can work anything.
To find the force exerted, we can use the formula for work: ( \text{Work} = \text{Force} \times \text{Distance} ). Rearranging gives us ( \text{Force} = \frac{\text{Work}}{\text{Distance}} = \frac{1470 , \text{joules}}{20 , \text{meters}} = 73.5 , \text{newtons} ). To convert this force to pounds, we can use the conversion factor ( 1 , \text{newton} \approx 0.2248 , \text{pounds} ), resulting in a weight of approximately 16.56 pounds for the bowling ball.
To find the time it takes for the motor to raise the boiler, we first calculate the work done against gravity, which is given by the formula ( \text{Work} = \text{Force} \times \text{Distance} ). Here, the work done is ( 9800 , \text{N} \times 10 , \text{m} = 98,000 , \text{J} ). The power of the motor is 1200 W, which is equivalent to 1200 J/s. Therefore, the time taken is ( \text{Time} = \frac{\text{Work}}{\text{Power}} = \frac{98,000 , \text{J}}{1200 , \text{W}} \approx 81.67 , \text{s} ).
It means that the text is too short to be able to work and/or fit.
Lifting a 50 newton weight 3 meters straight upward requires more work than lifting a 30 newton weight the same distance. Work is calculated using the formula ( \text{Work} = \text{Force} \times \text{Distance} ). For the 50 newton weight, the work done is ( 50 , \text{N} \times 3 , \text{m} = 150 , \text{J} ), while for the 30 newton weight, it is ( 30 , \text{N} \times 3 , \text{m} = 90 , \text{J} ). Thus, lifting the 50 newton weight involves more work.