The answer is 135.
15 times 9 equals 135
27 times 5 equals 135
040
Any number is divisble by all of those. Did you mean what is a NATURAL number divisible by those? That I am too lazy to find out.
yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6
30
3 and 5 are divisable by 195
any number evenly divisble if it ends in 0 or 5
Any number that ends with 5 or 0 except 0 itself is divisble by 5
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
yes for a number to be divisble by 3 you have to add the numbers together and see if you can divide it by 3 evenly 1+5+3= 9 9 can be divided by 3 evenly so that makes the number, 153 divisble by 3
2520
They are divisble by 5 because every number at the end if it ends in 0 or 5 then its divisble by 5.
36360 is a 5 digit number that is divisible by both 3 and 9.
yes it is because 90 has a 0 at the end if the end of the number is 0 or 5 it is divisble by 5
by 3 . . . yes by 5 . . . no
All those that end with 0 or 5 are divisible by 5. That would be 1000, 1005, 1010, ... 9990, 9995. There are 900 such numbers.
Any of its multiples
285
It is: 405/5 = 81
There are infinitely many numbers divisible by 2, 3, 5 and 9. One such is 900.
99324 (the third digit is 3)3+2=5
99987
It is 500.
1
Except for 5 itself, the units digit of a prime can't be 5. Any number ending in 5 is divisible by 5.
9000 is one.