The Phi angle is usually the second unknown angle after theta. It is typically used in the argument of a complex number, the phase of a wave in signal processing, in spherical coordinates, as one of the dihedral angles in the backbones of proteins in a Ramachandran plot, and as the internal or effective angle of friction.
tan (phi)= (V* sin (theta) + Ia*Xs)/(V*cos (theta) +Ia*ra) theta is power factor angle torque angle= phi-theta
It's actually cos phi, where the Greek letter, 'phi', is the symbol for phase angle -the angle by which a load current lags or leads the supply current in an a.c. system (the Greek letter, 'theta', is used for the displacement of instantaneous values of current or voltage from the origin of a sine wave).The reason why power factor is a cosine requires you to understand the relationship between apparent power, true power, and reactive power. Apparent power is the vector sum of true power and reactive power, and can be represented, graphically, by the so-called 'power triangle'. In the power triangle, true power lies along the horizontal axis, reactive power lies along the perpendicular axis, and the apparent power forms the hypotenuse, and the angle between true power and apparent power represents the phase angle. By definition, power factor is the ratio between true power and apparent power, and this ratio corresponds to the cosine of the phase angle.From this, we can conclude that true power = apparent power x cos phi, where 'cos phi' is the 'factor' by which we must multiply apparent power to determine true power -i.e. the 'power factor'.
3 phase kVA = V*I*sqrt(3) Where voltage is line to line, and current is the actual RMS current flowing in the a wire. kW = V*I*sqrt(3)*Cos (phi), where phi is the angle between the voltage and current; Cos (phi) is also known as the power factor. kVA is the vector sum of kW (real power) and kVAR (reactive power). As the equations above suggest, you must know the voltage to correctly calculate the current.
There is no SI symbol, as such, for power factor. As power factor is the cosine of the phase angle (the angle by which the load current leads or lags the supply voltage), power factor is normally written as 'cos' followed by the lower-case Greek letter we pronounce 'phi' (I've no idea how to type a Greek letter in this answer!).
To answer this we assume that the current in a passive component can be written as: i(t) = I*cos(wt +phi), where I is the constant current amplitude for a resistor: V=IR, v(t) = A*R*cos(wt+phi) thus, V = I*R angle(phi) for a capacitor: i(t) = C*(dv/dt) v(t) = V*cos(wt +phi) dv/dt = V*w*sin(wt +phi) therefore: i(t) = wCV*sin(wt + phi) v(t) = V*cos(wt +phi) from this it is clear that the current in a capacitor is 90degrees out of phase (sin->cos 90degrees difference) and that the current amplitude is dependent on capacitance value and frequency (w=2*pi*f). remember because capacitors are not ideal the 90degree phase shift will vary and be dependent on paracitic elements such as parallel/series resistance and series inductance.
Because it has to be 1 when the phase angle is zero.
tan (phi)= (V* sin (theta) + Ia*Xs)/(V*cos (theta) +Ia*ra) theta is power factor angle torque angle= phi-theta
The golden ratio, phi occurs many places in the platonic solids. The dihedral angle on the dodecahedron is 2*atan(phi), and the dihedral angle on the icosahedron is 2*atan(phi2) or 2*atan(phi + 1). The mid radius of the dodecahedron is similarly phi2/2 or (phi + 1)/2, and the mid radius on the icosahedron is phi/2. There are several other measures within Platonic solids which involve phi.
BY sukin a chorizo
120 degrees. Go mountaineers!
i know that static capacitors are used to improve the power factor. power factor should be high. Static capacitor supplies lagging reactive power. That means; the current I has 2 components they are magnetising Im (watless or waste current) and useful current Iw. Iw is in phase with voltage and Im is 90 degree away. Phase angle between them is phi 1. power factor is given by cosine of phi 1. phi angle should be less so that cosine of phi is high. To make phi angle less we use capacitor; this is nothing but power factor correction and capacitor used for this is called power factor correction capacitor. now when a capacitor is connected, it induces a current Ic 180 out of phase from Im and less in magnitude from Im. therefore, now the magnetising current is Im1=Im-Ic. due to this the phase angle reduces to phi 2. now the new power factor is cosine of phi 2. it is improved power factor.
phi
Yes.If the angle between them is 90 degrees. As we know that A.B=|A| |B| cos (phi). When phi=90 degree,cos 90=0. Hence A.B= |A| |B| *0 =0.
Three phases conditions are: 1. there should be three wires for carrying current and voltage. 2. the current and voltages should be sinusoidal in nature i.e A.C voltages or currents. 3. phase angle should be 120 degree apart for each line voltages or current. Suppose voltage of the first line is given by: Va= Vsin(phi) Then second and third line voltages will be: Vb=Vsin(120-(phi)) and Vc=Vsin(240-(phi)) where (phi) is the phase angle and V is the supply voltages which has same magnitude in all the three phases.
The passive earth pressure occurs when when a wall or plane moves towards earth. This will create additional pressure where as in the case of active pressure wall moves away from earth and it will reduce the pressure on the wall. From the co-efficient of active earthpressure and passive earthpressure,i.e Ka = 1-sin( phi)/1+sin( phi) Kp = 1+sin( phi)/1-sin( phi where phi is the angle of internal friction of soil.
Delta Phi was created on 1827-11-17.
(a+b)/a=a/b=phi (the golden ratio, as defined) (a+b)/a=phi (we'll solve this equation) 1+b/a=phi (just changing the form of the left side a little) 1+1/phi=phi (a/b=phi so b/a=1/phi) phi+1=phi2 (multiply both sides by phi) phi2-phi-1=0 (rearrange) From here, we can use the quadratic equation to find the positive solution: phi=(-b+√(b2-4ac))/(2a) phi=(1+√(1+4))/2 phi=(1+√5)/2≈1.618