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# What is a Uniformly distributed load?

## Answer

###### Wiki User

###### October 22, 2010 4:34PM

A **uniformly distributed load** (UDL) is a load which is
spread over a beam in such a way that each unit length is loaded to
the same extent.

## Related Questions

###### Asked in Civil Engineering, Electrical Engineering

### What is uniformly distributed load?

UDL = Uniformly Distributed Load
UDSWL = Uniformly Distributed Safe Working Load
UDL describes the way in which a load or weight is spread across
a shelf area. Imagine a fish tank exactly the same size as the
shelf; as you fill it with water, it finds its' own level so the
load transmitted to the shelf is uniformly distributed.

###### Asked in Mechanical Engineering

### How do you calculate reactions for a simply supported beam loaded with a uniformly distributed load?

For finding reactions for simply supported beam with uniformly
distributed load, first we have to convert the u.d.l into a single
point load. And then we have to consider it to be a simply
supported beam with a point load and solve it. I think you know how
to calculate the reactions for beam with point load.

###### Asked in Civil Engineering

### What is uniformly distributed loads?

Uniformly distributed loads are loads which have loading
distributed evenly across a span of length "L". Written as kips/ft
in U.S. customary units. Uniformly distributed loads can be
considered a point load acting at the center of a simply supported
span when you multiply load per foot by the length of the span. EX)
A uniform 200 kips/ft load is placed on a simply supported beam 10
feet in length. (200 kips/ft)*(10ft)=2000 kips concentrated load
acting at the mid span, (L=5ft). This information can be used to
determine shear and moment diagram for design considerations.

###### Asked in Civil Engineering, Mechanical Engineering, Statics

### How do you calculate the bending moments for a uniformly distributed loads with point loads?

A uniformly distributed load will have the same effect on
bending moment as a point load of the total weight of the
distributed load applied at the center of the distributed load.
If you reduce the uniformly distributed load to a point load, it
can be calculated in the same manner as, and along with, the other
point loads.
A bending moment is the distance times the point load,
remembering to take direction into account. They can be added
algebraically.
Example: assume we have a 10 meter beam with a point load
of 10 kg at 1 m and a uniformly distributed load of 10 kg/m from 2
m to 4 m. Reduce the distributed load to (10 kg/m * 2 m) or 20 kg
applied 3 m out. You now have two point loads: 10 kg at 1 m, and 20
kg at 3 m. The problem then becomes (10 kg * 1m) + (20 kg * 3 m) or
10 kg-m + 60 kg-m = 70 kg-m.
If the load is not uniformly distributed, this same principle
can still be applied by finding the total weight applied and the
center of gravity of the distributed load and applying that full
load as a point load at the point of the center of gravity.
Example: assume we have a distributed load of the form 2 kg/m
from 0 to 6 m. We know that the general shape of this load
distribution will be triangular. We know that the center of gravity
of a triangle is 1/3 the width of the triangle from the highest
point of the triangle. The highest point will occur at 6 m. 1/3 in
from that is at 4 m. That's our point of application. Our total
weight is the integral from 0 to 6 of 2 kg/m dx (or 1/2 6 * 12) =
36 kg. So we assume a point load of 36 kg applied at 4 m for a
bending moment of 144 kg-m.

###### Asked in Civil Engineering, Mechanical Engineering

### What is formula for maximum load due to bending of a simply supported beam?

The strength, S, of the beam is Mc/I where M = max moment to
fail = PL/4 for load concentrated in the middle of the beam or WL/8
for uniformly distributed load.
Here P is the concentrated load, W = distributed load, c =
distance to outer fiber from neutral axis and I the area moment of
inertia of the beam. L = length
Solving for load maximum,
P = 4IS/Lc for concentrated center load
W = 8IS/Lc for distributed load

###### Asked in Chemistry

### What are the two categories of mixtures?

The two categories of mixtures are heterogeneous and
homogeneous. In a homogeneous mixture the components are uniformly
distributed throughout the mixture. Homogeneous mixtures are
solutions, such as salt water. In a heterogeneous mixture, the
components are not uniformly distributed, such as granite, or
pizza.

###### Asked in Mechanical Engineering

### What is a uniformly varrying load?

these are the load varrying uniformly from zero to a particular
value and spread over a certain length of the beam.Such load is
also called triangular load.The total load can be obtained by
calculating the total area of triangle & multiplied if by the
intensity or rate of loading.The total load will act through the
centroid of the triangle.

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