Why you are using 10.94 ml of milk in butyrometer for fat analysis in milk?
The buyrometer graduation is so calibarated each 1% of
graduation in the buty rometer will occupy 0.125ml of fat.(i.e) the
weight of the fat in the area is equal to v X D =Mass; 0.125 x 093
= 0.1125. If 1 % represents 0.1125 then 100 % will represent 11.25
g. The average specific gravity of milk is 1.032 so the volume of
milk is to be taken to cent percent is 11.25 / 1.032 = 10.9 (i.e.)
11 ml