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5 m/s2
Acceleration = (change in speed) divided by (time for the change) = (9/3) = 3 m/s2
The answer will be 5 m/sec/sec 300m/sec - 200m/sec divided by 20 seconds will get you 100m/sec divided by 20 seconds, which then equals 5
The car's uniform acceleration is (change in speed) divided by (change in time) = (24 m/s) / (2.95 s) = 8.1356 meters/sec2. Call this number ' A ' for acceleration. Change in speed = ( A ) times (time) Time = (change in speed) / A = (20 - 10) / A = 10/A = 0.81356 seconds (rounded)
The car's final velocity will be 37.68 meters per second / 84.3 mph
5 m/s2
Acceleration = Change in speed/Time Time = Change in Speed/Acceleration = 65mph/20mph per s = 65/20 seconds = 3.25 seconds
-- "Acceleration" is any change of velocity.-- "Velocity" is a speed and its direction.-- "20 meters per second" is a speed, not a velocity, because it doesn't mention a direction.-- We don't have enough information to say anything about that car's acceleration.If, for example, it happens to be moving at a constant speed of 20 meters per secondon a circular track, then it has plenty of acceleration.
Average acceleration = (change in speed) divided by (time for the change)= (80) / (20) = 4 meters per second2
Acceleration = change in speed/time = (20-5)/3 = 15/3 = 5 units of speed per second. It is not possible to be any more precise because the unit of speed (kilometres per hour, miles per hour, metres per second) is unspecified.
The formula for finding time based on acceleration and speed is: (Delta)t = (Delta)v/a Change in time = change in speed / acceleration t = 75-15 / 20 t = 60 / 20 t = 3 seconds
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
Remember the equation for acceleration. a = (v - u ) / t Were a = acce;leration v = final speed ( 20 m/s) u = initial speed ( 0 m/s) t = time ( 5 s) Substituting a = ( 20 m/s - 0 m/s) / 5s a = 20m/s / 5s a = 4 m /s^2
Magnituide of acceleration = (change in speed) divided by (time for the change)= (final speed - initial speed) divided by (time for the change)= 2/20 = 0.1 meter per second2Note that this is the magnitude of the acceleration, obtained by working with the speeds.We don't know the initial or final velocities, because there's no information regarding directions.Similarly, we only know the magnitude of the acceleration, not its direction.
Acceleration = (change in speed) divided by (time for the change) = (9/3) = 3 m/s2
In general, the acceleration during that time interval could vary considerably. However, we can calculate the average acceleration during the interval. The change in speed is 20 meters per second - 5 meters per second = 15 meters per second, and this change in speed occurs over a 3 second interval. Thus the average change in speed over this interval is 15 meters per second/ 3 seconds = 5 meters per second per second = 5 meters/second2
It increases by 20 centimetres per second in the given direction for each second that elapses.