162.56 cm
Let the circumference be (x-3) and the height be x: circumference*height = curved surface area (x-3)*x = 54 square cm x2-3x = 54 x2-3x-54 = 0 Solving the above quadratic equation works out as: x = -6 or x = 9 it must be the latter because dimensions can't be negative. Therefore: height = 9 cm and circumference = 6 cm Check: 6*9 = 54 square cm
Let its height be x:- Area of the isosceles trapezoid: 0.5*(sum of parallel sides)*height Perimeter: 32-7-7 =18 which is sum of parallel sides Area: 0.5*(18)*x = 54 Height: (54*2)/18 = 6 cm Check: 0.5*(18)*6 = 54 square cm
150 ft (46 m) for the Montu's height; 54 in (137 cm) for a person.
12x9=108 108/2=54 54cm
Quokkas are not generally measured in height, but in head to body length, which gives a rough range of the quokka's height. They have a head to body length of between 41 cm and 54 cm, with a tail length of 25 - 31 cm.
To find the volume of a rectangular prism with dimensions 3 cm, 6 cm, and 3 cm, you multiply the length, width, and height together. The volume is calculated as ( V = \text{length} \times \text{width} \times \text{height} = 3 , \text{cm} \times 6 , \text{cm} \times 3 , \text{cm} = 54 , \text{cm}^3 ). Thus, the volume is 54 cubic centimeters.
Area = 0.5*(3.5+5.5)*12 = 54 square cm
4 ft = 48 inches. So 4 ft 6 in = 48 in + 6 in = 54 in. There are 2.54 cm in an inch, so (54 in) * (2.54 cm/in) = 137.16 cm
Weight:119 lbs or 54 kgHeight:5′ 5½” (166 cm)
Weight 120 lbs 54-55 kg Height 4-6 inches 164-165 cm
Let the other diagonal be x:- If: 0.5*x*12 = 54 Then: x = 54/6 => 9 The rhombus will consist of 4 right angles: base 4.5 cm and height 6 cm Using Pythagoras: hypotenuses = 7.5 cm Therefore perimeter: 4*7.5 = 30 cm
It is: 42+42+54+54+63+63 = 318 square cm