It's been a long while since chem, but perhaps this will put you on the path. When they're talking about "half reaction" I believe they're referring to one side or the other, of the balanced equation -- what forms from what. In the case of solid copper and silver nitrate, the copper "takes" the NO3 and leaves the silver, previously in solution, to remain as a solid.
Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag
The spectator ions are Ag+ and (NO3)-.
Some of the silver ions from the silver nitrate solution are deposited as metallic silver on the contacted parts of the zinc vessel and are replaced by half as many zinc ions in the solution.
There are two main types of reactions used for extracting copper form its ore. In one reaction, copper oxides reduced by carbon to produce carbon dioxide and pure copper. In the second reaction, Copper ore is dissolved, then reduced by iron ions to form Cu+ which forces the copper to let go of its impurities and these copper ions are then fully reduced by a chemical reaction to form Copper metal. See related links for more information about the second reaction.
The reaction you describe in words is: KCl + AgCH3CO2 → AgCl + KCH3CO2 This type of reaction is known as a "double replacement reaction" aka "double displacement reaction" aka "metathesis reaction." A double replacement reaction is a chemical reaction where two reactant ionic compounds exchange ions to form two new products compounds with the same ions. In this case the ions are K+ , Cl-, Ag+ and C2H3O2−. Note that potassium chloride (KCl), silver acetate (AgCH3CO2) and potassium acetate (KCH3CO2) are all quite soluble in water. Silver chloride (AgCl) is not particularly soluble in water (520 μg/100 g at 50 °C) and will precipitate out as the reaction occurs.
The reaction product of Fenton's reagent (a solution of hydrogen peroxide and ferrous iron) with silver is typically silver oxide (AgO) or silver hydroxide (AgOH) depending on the conditions of the reaction. These products are formed when the silver ions present in the solution react with the hydroxyl radicals generated by Fenton's reagent.
With what? Not enough detail, but silver is not very electropositive. Pretty much any compound or chemical entity can be involved in a redox reaction of some kind. The obvious redox reaction involving silver nitrate would involve silver ions being reduced to silver metal, plus some corresponding oxidation reaction.
The chlorine is reduced to chloride ions and the iodide {note correct spelling} are reduced to elemental iodine.
A displacement reaction, in which the copper dissolves to form copper nitrate and replaces silver ions in the original silver nitrate, reducing the silver ions to metallic silver.
Silver ions are only one half of a ionic bond. Take a simple ionic compound, one half of which is silver, for example silver bromide. This contains both Ag2+ (silver) and Br-(Bromine) ions. The bonds between these two different ions are ionic bonds
These Copper(II) ions are reduced to insoluble Copper(I) ions, while the reaction.
The reaction of chlorine with potassium bromide is a reduction-oxidation reaction. The chloride oxidizes bromide ions to molecular bromine, and itself is reduced to chloride ions.
The spectator ions are Ag+ and (NO3)-.
The silver ions in the exposed area will be reduced to black metallic silver in a matter of minutes.
The spectator ions are Ag+ and (NO3)-.
Oxidant half reaction: 2H+ + 2e- --> H2 Reductant half reaction: Fe --> Fe2+ + 2e- Tribune ions: 2Cl- --> 2Cl-
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
In the half reaction where an oxygen molecule becomes into two oxide ions, it obtains 4 electrons from the oxidising substance.