No. The mole of solution is equal to mole of solute plus mole of solvent (solVENT !, not solution)
1
Because when one mole of solute is added the volume of water becomes changed, so take 1 mole solute in an empty container then add water and make it one litre.
Mole is the molecular weight of a compound in grams.Mass is the mass of the solute dissolved in the solution.Molar concentration is the number of moles of the solute in the unit of volume of the solution.Volume is expressed in a unit of SI.
The molecular weight. So you'll have to calculate that for the solute first. The molar mass of the solute, which is measured in grams/mole.
No. The mole of solution is equal to mole of solute plus mole of solvent (solVENT !, not solution)
The molar mass of benzene (C6H6) is 78.11 grams per mole. The molar mass of toluene is 92.14 grams per mole. Mole fraction of a solute equals moles of solute divided by the moles of solute plus the moles of solvent. .5 of each is the mole fraction.
1
Because when one mole of solute is added the volume of water becomes changed, so take 1 mole solute in an empty container then add water and make it one litre.
Depending on the molecular mass of the solute.
0.0613 mole fraction = moles solute/(moles solute + moles water) moles water = 1000 g / 18.02 = 55.49 3.62/(55.49 + 3.62)=0.0613
solute can be solid, liquid or gas.One should remember that state of solution is determined by state of solvent.Ex- in a mixture of 1 mole Hg and 1 mole metal the solute is Hg and solvent is metal as solution which is an alloy is solid.
Molarity is one mole of solute per 1000 ml of solution
This is the ratio between the molar concentration of this solute and 3,3.
number of moles is mass divided by molecular mass. the molecular mass of NaCl is 58.44g/mol. therefore you need 58.44g to make one mole
molarity = number of moles of solute / volume of solution number of moles of solute = molarity x volume of solution number of moles of solute = 12 (mole/L) x 15/1000 (L) number of moles of solute = 0.18 mole
molal = m = moles solute/kg solvent. Assuming water as the solvent 1 kg = 1000 g/18g/mole = 55.56 moles H2O. Moles solute = 3.71 moles. Total moles present = 55.56 + 3.71 = 59.27 moles.Mole fraction solute = 3.71/59.27 = 0.0626