bad cab cad dab
(A + B) + C = A + (B + C) = A + B + C
The associative property states that the result of an addition or multiplication sentence will be the same no matter the grouping of the terms. Associative: (a + b) + c = a + (b + c) (a × b) × c = a × (b × c)
C is the only sentence in the passive voice.
The simplest one to use is cross multiplication. Suppose a/b and c/d are two fractions with positive integers a, b, c and d. Then a/b > c/d if and only if a*d > b*c a/b = c/d if and only if a*d = b*c a/b < c/d if and only if a*d < b*c Other methods, such as equalising the numerator or denominator, or converting to decimal will, in general require more effort.
A) 2001, only for Gamecube. B) WHY? C)GO TO ENGLISH CLASS.
This is a question of permutation. There are only 3 ways. A-B-C, B-C-A, C-A-B
the answer is c
This cannot be answered. This question does not make sense.
a/b = c/d if and only if a*d = b*c.
Question:What are the majority of hand tools made from.Is It: A~Stainless steel B~Aluminum C~Plastic D~All of the above E~A and B only The answer is D~All of the above
Yes. To show the conditions on a, b, c and d given that if a/b = c/d then a+b = c+d. Suppose b != d (and that both b and d are non-zero) then: d = kb for some number k (!= 0), so c/d = c/kb = (c/k)/b so a/b = (c/k)/b => a = c/k => c = ka Thus: c + d = ka + kb = k(a + b) Which means that c + d = a + b only if k = 1. Thus if a/b = c/d then a + b = c + d only if a = c and b = d. The condition on b and d both being non-zero prevents the possibility of division by zero. If either is zero, a division by zero will occur and at least one of the fractions is infinite.
exactly one and only one.