ax - b = c
Add 'b' to each side:
ax = b + c
Divide each side by 'a':
x = (b + c) / a
x = b/(a + c)
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
(a + b + c)3 = a3 + b3 + c3 + 3(a2b + ab2 + b2c + bc2 + ca2 + ac2) + 6abc
657
49 + c units
a - b = c -(a - b) = -c b - a = -c
x(-b)=m(x-c)
complement of c
C minus B equals AB
x = b/(a + c)
well if the coefficient of a times the negative reciprical of b equals 4.33 then if you add all of them they should be able to fit in as themselves int the equation: x=-b(plus or minus) (the sqare root of:(b)(b)+-4ac) all divided by 2a, the basic quadratic equation its elementery me dear lad
A=0 b=0 c=0
When b is zero.
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
its B
It equals b times c.