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velocity is 1st derivative of distance with respect to time

acceleration is 2nd derivative of distance with respect to time

dx/dt = velocity = 3t^2

dv/dt = acceleration = 6t

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Q: What is acceleration of a particle if position of a particle at any instant of time t is given by x equals t 3?
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When is acceleration equals half of the sum of initial and final velocities?

If you have a particle with constant acceleration, and you add the initial and final velocities and then divide them by two, what you get is the average velocity of the particle in that period of time.


The displcement x is m from the equilibrium position of a particle moving with SHM is given by x equals 0.05sint where t is the time in seconds measured from an instant when x equals o state the ampli?

The amplitude of the Simple Harmonic Motion is 0.05.


A particle moves so that its position in m. as a function of time in sec is r equals i plus 4Tsqj plus tk. write expressions for a. its velocity and b. its acceleration as functions of time?

R = [ i + 4T2j + Tk ] a). Velocity = R' = [ 8Tj + k ] b). Acceleration = R'' = [ 8j ]


If acceleration equals zero does velocity equal zero?

No.Any body traveling at a steady speed is experiencing velocity without experiencing acceleration. So a for particle traveling steadily at 3m/s, velocity equals 3 m/s, but as long as it travels steadily at this rate, acceleration is 0.


Is it possible that a particle has zero velocity but still have a acceleration?

If the velocity equals zero, the acceleration is also zero because the velocity hasn't changed, thus, the particle isn't accelerating anywhere. This is not exactly true; at an instant in time the acceleration can be non-zero while the velocity is zero. However, this would change the velocity to non-zero after any amount of time. An example of this is when you throw a ball into the air: at it's highest point, the velocity is zero (it changes from going upward to going downward, passing through zero for an instant). However the acceleration is downward the entire time.


How do you find the acceleration for a moving object?

Divide the change in position, (total distance covered) by the time it took. Xf = xi +at a = xf-xi / t That is the definition of velocity, not acceleration. Acceleration is rate of change of velocity. (vfinal - vinitial)/t for constant acceleration so vf equals vi + at. Or a equals dV/dt otherwise.


What is the minimum acceleration for a particle in simple harmonic motion obeying x equals acos2t?

Acceleration is a vector, so it has both magnitude and direction.A particle in the simple harmonic motion, x = a cos(2t), has an acceleration that varies between positive and negative extremes (+4a and -4a) at the end points of its motion and has zero acceleration as it passes through its center of motion.Here is the mathematics.Position ' x ' = a cos(2t)Velocity ' v ' = dx/dt = -2a sin(2t)Acceleration = dv/dt = -4a cos(2t)The minimum instantaneous magnitude of acceleration is zero,and its most negative instantaneous value is [ -4a ].


How do you find speed from acceleration and time?

speed equals to acceleration into time


How does heat travel by conduction?

Heat, on a molecular or atomic level, is kinetic energy; fast moving particles are literally hotter. So, if a fast moving particle collides with a slower particle, there will be an exchange of energy. We know from basic physics that force equals mass times acceleration, so when a force is applied to a particle, that particle will accelerate. That is how heat is transferred particle by particle. All of this happens on such a small, sub-microscopic scale, that we do not see the mechanics of it, we just see heat being conducted.


Is this right force equals mass divided by acceleration?

No. Force = mass x acceleration.


Acceleration equals force divided by mass?

No


What happens to the acceleration when mass and force are doubled?

Acceleration remains the same. Remember that Force equals Mass times Acceleration, or Acceleration equals Force divided by Mass. So, if both Force and Mass double, Force Divided by Mass remains the same.