0
What else can I help you with?
What is compare instruction 8086 microprocessor?
the compare instruction of 808 is used to compare the 2 operands. syntax: cmp op1,op2 algorithm: op1-op2 the value of the operands are not affected only the flags are updated if op1<op2 carry=1 and zero flag=0 if op1=op2 cy=0 and zf=1 if op1>op2 cy=0 and zf=0
How do you do java calculator project?
import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
How do you create a java calculator?
I made this in bluej(Free Java compiler) import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
A complete java code to make calculator?
import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
How do you make a scientific calculator program in java?
import java.io.*;import java.util.*;public class Calculator{public static void main(String args[]){System.out.println("Make your arithmetic selection from the choices below:\n");System.out.println(" 1. Addition");System.out.println(" 2. Subtraction");System.out.println(" 3. Multiplication");System.out.println(" 4. Division\n");System.out.print(" Your choice? ");Scanner kbReader = new Scanner(System.in);int choice = kbReader.nextInt();if((choice0)){System.out.print("\nEnter first operand. ");double op1 = kbReader.nextDouble();System.out.print("\nEnter second operand.");double op2 = kbReader.nextDouble();System.out.println("");switch (choice){case 1: //additionSystem.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) );break;case 2: //subtractionSystem.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) );break;case 3: //multiplicationSystem.out.println(op1 + " times " + op2 + " = " + (op1 * op2) );break;case 4: //divisionSystem.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) );}}else{System.out.println("Please enter a 1, 2, 3, or 4.");}}}Read more: How_do_you_make_calculator_program_in_java
How easy is it to get a OP1?
It is easy if you study hard and Ace all of your six subjects. Including subjects that you are good at.
Solution to 5 and 4 equals 4 in python programming?
The Boolean OP1 AND OP2 operates bit-by-bit, setting a 1 in the result if the corresponding bit in OP1 and OP2 are both 1's. A similar operation is the Boolean OP1 OR OP2 which sets a 1 in the result of the corresponding bit in either OP1 or OP2 are both 1.The number 5 is 101 in binary, while the number 4 is 100 in binary, so ANDing 5 and 4:101100=100Since the "ones" bit is 1 in the number 5 and not in 4, it is zero in the result.In Python the AND operator is "&", therefore in Pythona = 5 & 4"a" will be 4.
What java can do?
Java is used just about everywhere. Your phone, television, computer etc. Java is the most popular programming language. Example of Java: import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
What is an algorithm to evaluate prefix expression using stack with example?
I HOPE THIS WILL HELP U OUT...ALGO GOES LIKE THIS: Reverrse prreffiix and evalluatte iittreverse given prefix expression;scan the reversed prefix expression;for each symbol in reversed prefixif operand thenpush its value onto stack S;if operator then {pop operand1;pop operand2;compute result = operand1 op operand2;push result back onto stack S;}return value at top of stack;AND EXAMPLE IS:Prefix: */-abc-+def Reversed: fed+-cba-/*ch action stackf push fe push f ed push f e d+ pop op1 f epop op2 fcalc &push f (d+e)- pop op1 fpop op2calc & push ((d+e)-f)c push ((d+e)-f) cb push ((d+e)-f) c ba push ((d+e)-f) c b a- pop op1 ((d+e)-f) c bpop op2 ((d+e)-f) ccalc & push ((d+e)-f) c (a-b)ch action stack/ pop op1 ((d+e)-f) cpop op2 ((d+e)-f)calc & push ((d+e)-f) ((a-b)/c)* pop op1 ((d+e)-f)pop op2calc & push ((a-b)/c)*((d+e)-f)
Calculate the z-score for a test score of 87 if the mean test score is 81.1 and standrd deviation is 11.06?
z score = (test score - mean score)/SD z score = (87-81.1)/11.06z score = 5.9/11.06z score = .533You can use a z-score chart to calculate the probability from there.
Is score a verb?
Yes. It's the past tense of the verb to score.
How do you spell score in french?
a score in sports (like football) : le score (masc.)to score a goal: marquer un buta score (group of twenty): une vingtaine
