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What is compare instruction 8086 microprocessor?
the compare instruction of 808 is used to compare the 2 operands. syntax: cmp op1,op2 algorithm: op1-op2 the value of the operands are not affected only the flags are updated if op1<op2 carry=1 and zero flag=0 if op1=op2 cy=0 and zf=1 if op1>op2 cy=0 and zf=0
How do you create a java calculator?
I made this in bluej(Free Java compiler) import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
How do you do java calculator project?
import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
A complete java code to make calculator?
import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
How do you make a scientific calculator program in java?
import java.io.*;import java.util.*;public class Calculator{public static void main(String args[]){System.out.println("Make your arithmetic selection from the choices below:\n");System.out.println(" 1. Addition");System.out.println(" 2. Subtraction");System.out.println(" 3. Multiplication");System.out.println(" 4. Division\n");System.out.print(" Your choice? ");Scanner kbReader = new Scanner(System.in);int choice = kbReader.nextInt();if((choice0)){System.out.print("\nEnter first operand. ");double op1 = kbReader.nextDouble();System.out.print("\nEnter second operand.");double op2 = kbReader.nextDouble();System.out.println("");switch (choice){case 1: //additionSystem.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) );break;case 2: //subtractionSystem.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) );break;case 3: //multiplicationSystem.out.println(op1 + " times " + op2 + " = " + (op1 * op2) );break;case 4: //divisionSystem.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) );}}else{System.out.println("Please enter a 1, 2, 3, or 4.");}}}Read more: How_do_you_make_calculator_program_in_java
Solution to 5 and 4 equals 4 in python programming?
The Boolean OP1 AND OP2 operates bit-by-bit, setting a 1 in the result if the corresponding bit in OP1 and OP2 are both 1's. A similar operation is the Boolean OP1 OR OP2 which sets a 1 in the result of the corresponding bit in either OP1 or OP2 are both 1.The number 5 is 101 in binary, while the number 4 is 100 in binary, so ANDing 5 and 4:101100=100Since the "ones" bit is 1 in the number 5 and not in 4, it is zero in the result.In Python the AND operator is "&", therefore in Pythona = 5 & 4"a" will be 4.
How easy is it to get a OP1?
It is easy if you study hard and Ace all of your six subjects. Including subjects that you are good at.
What java can do?
Java is used just about everywhere. Your phone, television, computer etc. Java is the most popular programming language. Example of Java: import java.io.*; import java.util.*; public class Calculator { public static void main(String args[]) { System.out.println("Make your arithmetic selection from the choices below:\n"); System.out.println(" 1. Addition"); System.out.println(" 2. Subtraction"); System.out.println(" 3. Multiplication"); System.out.println(" 4. Division\n"); System.out.print(" Your choice? "); Scanner kbReader = new Scanner(System.in); int choice = kbReader.nextInt(); if((choice<=4) && (choice>0)) { System.out.print("\nEnter first operand. "); double op1 = kbReader.nextDouble(); System.out.print("\nEnter second operand."); double op2 = kbReader.nextDouble(); System.out.println(""); switch (choice) { case 1: //addition System.out.println(op1 + " plus " + op2 + " = " + (op1 + op2) ); break; case 2: //subtraction System.out.println(op1 + " minus " + op2 + " = " + (op1 - op2) ); break; case 3: //multiplication System.out.println(op1 + " times " + op2 + " = " + (op1 * op2) ); break; case 4: //division System.out.println(op1 + " divided by " + op2 + " = " + (op1 / op2) ); } } else { System.out.println("Please enter a 1, 2, 3, or 4."); } } }
What is an algorithm to evaluate prefix expression using stack with example?
I HOPE THIS WILL HELP U OUT...ALGO GOES LIKE THIS: Reverrse prreffiix and evalluatte iittreverse given prefix expression;scan the reversed prefix expression;for each symbol in reversed prefixif operand thenpush its value onto stack S;if operator then {pop operand1;pop operand2;compute result = operand1 op operand2;push result back onto stack S;}return value at top of stack;AND EXAMPLE IS:Prefix: */-abc-+def Reversed: fed+-cba-/*ch action stackf push fe push f ed push f e d+ pop op1 f epop op2 fcalc &push f (d+e)- pop op1 fpop op2calc & push ((d+e)-f)c push ((d+e)-f) cb push ((d+e)-f) c ba push ((d+e)-f) c b a- pop op1 ((d+e)-f) c bpop op2 ((d+e)-f) ccalc & push ((d+e)-f) c (a-b)ch action stack/ pop op1 ((d+e)-f) cpop op2 ((d+e)-f)calc & push ((d+e)-f) ((a-b)/c)* pop op1 ((d+e)-f)pop op2calc & push ((a-b)/c)*((d+e)-f)
Calculate the z-score for a test score of 87 if the mean test score is 81.1 and standrd deviation is 11.06?
z score = (test score - mean score)/SD z score = (87-81.1)/11.06z score = 5.9/11.06z score = .533You can use a z-score chart to calculate the probability from there.
Is score a verb?
Yes. It's the past tense of the verb to score.
How do you spell score in french?
a score in sports (like football) : le score (masc.)to score a goal: marquer un buta score (group of twenty): une vingtaine
