Applying a force through a distance is known as work. Work equals force in Newtons times distance in meters, and the unit for force is the Newton•meter, N•m.
Simply multiply force x distance. This assumes that the force is in the same direction as the movement.
distance
Don't know but my mate does
One definition of work is "Force acting through distance". The quantity of work is (force) multiplied by (distance through which the force acts). The 'dimension' of work is [Force] multiplied by [Distance]. "Newton" is a unit of force. "Meter" is a unit of distance. When you multiply a force measured in 'pounds', by a distance measured in 'feet', you get the amount of work done, measured in "foot-pounds". When you multiply a force measured in 'tons', by a distance measured in 'miles', you get the amount of work done, measured in "ton-miles". When you multiply a force measured in 'newtons', by a distance measured in 'meters', you get the amount of work done, measured in "newton-meters".
Ok, so a lever can be broken up into two 'sides' with a fulcrum in the middle. This idea simply utilizes the laws set forth for torque, or Force*distance. Static equilibrium (which would be when you input enough force on one side of the lever to balance the other) states the followingF1*D1 = F2*D2Starting from the left side of the lever, for have a force (F1) multiplied by the distance between that force and the fulcrum (D1). This can be set equal to the distance between the fulcrum and the second force, with this distance denoted as D2. If you want to know the input force, you need to know the other force, and both distances. Then you can simply divide. For example say want to know your input force, F2.F2 = (F1*D1)/D2Hope this helps
Simply multiply force x distance. This assumes that the force is in the same direction as the movement.
-- Magnitude of the force (or force as a function of time) -- Distance through which it acted (or position as a function of time) -- Duration of the time during which it persisted Work is the product of (force) x (total distance). Power is (work) divided by (duration of the time). If the force and distance are functions of time, then I'm not sure how to do it right now, but I know there's an integral in there somewhere, and I'm not happy about that.
distance
Don't know but my mate does
I don't know about you but i don't care
Power = (work) divided by (time) If you don't know the amount of work, you can calculate it. Work = (force) times (distance).
One definition of work is "Force acting through distance". The quantity of work is (force) multiplied by (distance through which the force acts). The 'dimension' of work is [Force] multiplied by [Distance]. "Newton" is a unit of force. "Meter" is a unit of distance. When you multiply a force measured in 'pounds', by a distance measured in 'feet', you get the amount of work done, measured in "foot-pounds". When you multiply a force measured in 'tons', by a distance measured in 'miles', you get the amount of work done, measured in "ton-miles". When you multiply a force measured in 'newtons', by a distance measured in 'meters', you get the amount of work done, measured in "newton-meters".
Out of the five numbers given in the question, we only need 2 of them in order to answer it.We don't care about the mass of the package, the time spent in the maneuver, or the friction force.All we need to know is that a force of 80 newtons moved through a distance of 25 centimeters.Work = (force) x (distance) = (80) x (0.25) = 20 joules .
Work is defined as (force) times (distance). If the force is not zero, and the distance it moved through is not zero, then work was done. In other words, if you applied a force, and kept it going while the place you applied the force moved, then work was done. In this case, work = (60) x (0.5) = 30 newton-meters = 30 joules of work.
True.
Ok, so a lever can be broken up into two 'sides' with a fulcrum in the middle. This idea simply utilizes the laws set forth for torque, or Force*distance. Static equilibrium (which would be when you input enough force on one side of the lever to balance the other) states the followingF1*D1 = F2*D2Starting from the left side of the lever, for have a force (F1) multiplied by the distance between that force and the fulcrum (D1). This can be set equal to the distance between the fulcrum and the second force, with this distance denoted as D2. If you want to know the input force, you need to know the other force, and both distances. Then you can simply divide. For example say want to know your input force, F2.F2 = (F1*D1)/D2Hope this helps
i dont know ,are you in 7se by any chance