Critical Velocity has the same dimensions as of velocity & terminal velocity. [L/T]
Discharge Velocity is obtained by Dividing the Total Discharge by the total cross Sectional Area , Where Total cross sectional area Consists of void+solid. In contrast .. Seepage Velocity is defined as the total discharge by the Area of voids only. So Seepage velocity always greater than Discharge Velocity.
None at all than we can think of. 'Velocity' means the speed and direction of motion. 'Area' means the size or extent of a flat surface.
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
The area under the velocity time graph of an object is equal to the distance travelled by that object in that time. This is because displacement is the integral of velocity with respect to time so integrating velocity from time A to time B will give the displacement from time A to time B. ( Integrating is the same as calculating the area under the graph)
yes it is
Critical Velocity has the same dimensions as of velocity & terminal velocity. [L/T]
Discharge Velocity is obtained by Dividing the Total Discharge by the total cross Sectional Area , Where Total cross sectional area Consists of void+solid. In contrast .. Seepage Velocity is defined as the total discharge by the Area of voids only. So Seepage velocity always greater than Discharge Velocity.
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You cannot. Velocity has nothing to do with volume and information on area, by itself, is not enough to determine the volume.
a graphical method to find velocity and acceleration of piston of a reciprocating engine
it is the velocity (V) divided by the retardation of the contaminant. The velocity, V is different from the regular velocity (which is Discharge/Area). V = regular velocity/porosity
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
its the velocity
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
Distance.
None at all than we can think of. 'Velocity' means the speed and direction of motion. 'Area' means the size or extent of a flat surface.