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What is the speed of a 2 kg ball that has a momentum of 10 kg per meter per second?
Momentum = M V = 10V = 10/M = 10/2= 5 meters per second
What is the momentum of a 2 kg toy truck that moves 10 meters per second?
Momentum = mass x velocity (p = mv)(2 kg)(10 m/s) = 20 kg m/s.
As and 10 kg in newton?
Assuming you are on Earth where the acceleration due to gravity equals 9.81 m/s^2 and Force (newtons) = mass ( kilograms) * acceleration ( m/s^2) then 10 kg * 9.81 m/s^2 = 98.1 Newtons.
What is the momentum of a 2 kilogram toy truck that moves at 10 meters per second?
liner momentum = p = mV = 2 kg * 10 m/s = 20 kg m/s
What is the acceleration of a 10 kg mass if a force of a 68.6 N is used?
The acceleration of the 10 kg mass can be calculated using the formula (a = F/m), where (F) is the force and (m) is the mass. Plugging in the values, we get (a = 68.6 N / 10 kg = 6.86 m/s^2), so the acceleration is 6.86 m/s².
Spaceship 1 and Spaceship 2 have equal masses of 200 kg Spaceship 1 has a speed of 0 m s and Spaceship 2 has a speed of 10 m s What is the magnitude of their combined momentum?
momentum = mass × velocity Assuming they are separate, the total momentum is 200 kg × 0 m/s + 200 kg × 10 m/s = 2000 kg m/s
What is the potential energy of a 5 kg object held 10 m above the ground?
The potential energy of the object is given by the formula: Potential Energy = mass * gravity * height. Plugging in the values (mass = 5 kg, gravity = 9.8 m/s^2, height = 10 m), we get: Potential Energy = 5 kg * 9.8 m/s^2 * 10 m = 490 J.
What is 0.03007kg in scientific notation?
m = 0.03007 kg in conventional notationm = 30.07 x 10^-3 in engineering exponential notationm = 3.007 x 10^-2 kg in scientific notation
Abox 5m long 2 m wide and 2m high applies 12 Pa of pressure to the table that it is resting on how much froce does the box?
The S.I. Units of Pascals(Pa) are kg m s^-2 m^-2 We need to find the area (m^-2) of the box resting on the table. Since it is 5 m long and 2 m wide then the area resting on the table is 10 m^2 Since the pressure is 12 Pa Then 12 Pa = kgms^-2 /10 m^2 This becomes 12 Pa x 10 m^2 = F(kg m s^-2 F = 120 kg m s^-2
When a 20 N force is applied to a 2 kg what is its acceleration?
The acceleration of the object would be 10 m/s^2, as calculated using Newton's second law where force is divided by mass (20 N / 2 kg = 10 m/s^2).
What is the force required to give a mass of 10 kg an acceleration of 5 ms²?
The force required can be calculated using Newton's second law, F = m * a, where F is the force, m is the mass (10 kg), and a is the acceleration (5 m/s^2). Substitute the values into the formula: F = 10 kg * 5 m/s^2 = 50 N. Therefore, a force of 50 Newtons is required to give a mass of 10 kg an acceleration of 5 m/s^2.
In an isolated system Bicycle 1 and Bicycle 2 each with a mass of 10 kg collide Bicycle 1 was moving to the right at 5 ms while Bicycle 2 was moving to the left at 3 ms What is the magnitude o their?
Magnitude of momentum before collision = (10 kg x 5 m/s) - (10 kg x 3 m/s) = 20 kg m/s. Magnitude of momentum after collision (assuming completely inelastic collision) = 20 kg m/s. Therefore, the magnitude of their combined momentum after collision will be 20 kg m/s.
