There are many ways to achieve this. Example:
#include <iostream>
using namespace std;
int main()
{
char str[256];
memset( &str, 0, 256 );
cout << "Enter a string with some spaces: ";
cin.getline( str, 256, '\n' );
int count = 0;
char * p = str;
while( p < str + 255 )
{
if( *p == 32 ) ++count;
++p;
}
cout << """ << str << "" has " << count << " spaces!" << endl;
return( 0 );
}
Read the characters one at a time, and write an "if" for each of the cases. In each case, if the condition is fulfilled, increment the corresponding counter variable.
SQL Server provides us with a variety of string functions. Some of them are:LOWER - To convert a string to lower caseUPPER - To convert a string to upper caseLTRIM - To trim blank spaces from the left side of the stringRTRIM - To trim blank spaces from the right side of the stringSUBSTRING - To pick up specific portions of a stringREVERSE - To reverse the input stringREPLACE - To replace the character at a specified position of a string with anotheretc.
There is no way. You need a username and password to play, and the program will not accept all blank spaces or dashes.
waht gose and the blank 2493_ _ _ _ 8008
Blank Spaces - 2010 was released on: USA: 22 February 2010 (internet)
use "\n" between the words where you want a new line
There were 3 blank spaces in mendeleev's Periodic Table. He left it for the elements which were not discovered at that time.
Paper with spaces
_______ program
yes
On his Periodic Table Mendeleev left the blank spaces, because he thought there would be elements that would follow his pattern.
#include<iostream> #include<fstream> int main() { std::ifstream infile ("example.txt", std::ios::in); unsigned chars(0); unsigned words(0); unsigned spaces(0); std::string delim("\t\n "); char ch(0); char last(0); if (!infile.good()) { std::cerr << "The filename is invalid." << std::endl; return -1; } while (infile.get(ch)) { switch (ch) { case (' '): case ('\t'): ++spaces; case ('\n'): // only count words if the last char was not a word delimiter if (delim.find(last) == std::string::npos) ++words; default: ++chars; } last = ch; } infile.close(); std::cout << "Number of chars:\t" << chars << std::endl; std::cout << "Number of words:\t" << words << std::endl; std::cout << "Number of spaces:\t" << spaces << std::endl; }