Cu2SO4
The formula for cuprous sulfide is Cu2S. Copper (I) or cuprous has a +1 charge, whereas Sulfur has a charge of -2. Cu^(-1) + S^(-2) -> Cu2S (The subscript is 2)
Cuprous iodide can be formed from potassium iodide by mixing a solution of copper(II) sulfate with potassium iodide. The reaction between the two compounds results in the precipitation of cuprous iodide, which is a solid compound. This solid can then be filtered and dried to obtain cuprous iodide.
Copper sulfate is not a metal There are two compounds called Copper Sulfate, which are salts of the metal Copper. CuSO4 is Copper (II) Sulfate, once known as Cupric Sulfate. Cu2SO4 is Copper (I) Sulfate, once known as Cuprous Sulfate.
React a solution of Copper(II) sulfate with Sodium Iodide. It will produce Copper(II) Iodide and Sodium sulfate. This Copper(II) iodide, due to instability, spontaneously decomposes, producing Iodine and Copper(I) Iodide.The Copper(I) iodide comes out as a yellowish brown precipitate. So the overall reaction seems to be:2 CuSO4 + 4 NaI ----> 2 CuI + 2 Na2SO4 + I2
The cuprous sulfide - Cu2S - is black.
a cuprous ion has 28 electrons.
In a solution of copper sulfate, the charge carriers that help it conduct electricity are the copper ions (Cu2+) and the sulfate ions (SO4 2-). These ions are free to move in the solution and carry electrical charge.
The chemical formula for cuprous fluoride is CuF.
Actually, the answer Cu(NO3)2 is incorrect for cuprous nitrate. Cu(NO3)2 is in fact cupric nitrate. Cuprous nitrate is represented as CuNO3 alone.
The chemical formula for cuprous arsenide is Cu3As.
Cuprous salts are typically white or pale yellow in color.
The charge on cuprous ion is +2. It is written as Cu2+.