its kanno your sir
The Intel 8080 was the first microprocessor using an 8 bit databus.
Databus is flow of information called data through a channel. That transportation of information could be serial or parallel. Serial data can be transported basically in two wires circuit, and parallel data is transported through as many wires as its quantity of bits (resolution of the information) Also databus can be in only one direction or both direction.
databus
The first IBM PC (the IBM 5150) used the Intel 8088 a version of the Intel 8086 with a multiplexed 8 bit databus instead of the full width 16 bit databus, to reduce package size and cost. IBM had also considered using the Motorola 68008 a version of the Motorola 68000 with a multiplexed 8 bit databus instead of the full width 16 bit databus, to reduce package size and cost; but Motorola could not promise delivery until a year later (due to fabrication problems) and Intel had their chip ready on the shelf.
An 8 bit microprocessor is a 'microprocessor' which only has an 8 bit wide databus.
The 8088 was a 16 bit microprocessor implemented on an 8 bit databus.
Its 16bit microprocessor,and-> the 8086 has a 16bit databus 20bit address bus-> the intel 8086,is designed to operate in two modes namely(1) minimum mode(2) maximum mode
The Macintosh 128K had 128k DRAM, and a 16 bit databus. Originally called the Macintosh Apple, a personal computer, not bad for the $2,495 introductory price released in January 1984.
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