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What is the width of a pencil?
The width of a pencil would be the metric unit of centimeters
When the height of a box shaped object is multiplied by its width and lenght its volume is found?
That is correct. Volume is height x length x width.
What is the weight channel iron?
depends on the width and each width can have up to 3 distinct weights?
What is the width of a water bottle?
that's a very vauge question. width would be the diamater when it is standing upright.
Is density the same as width?
no because density is how dense it is (how low the object or thing is) but width is how thick or thin the object is.
How to calculate bite angle effective working dia forward slip?
Effective diameter = Barrel Diameter - (Average pass height + Roll Gap) Average pass height = Area/pass width
What are the voucher codes for street mobster game?
{| class="tdefault" | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |} ---- === === === === === === === ===
What is the class width of the class interval 4-15?
class width is a width width is a width nothing as class width is a width dont be confuse
The perimeter of a rectangle is 16 times the width the length is 12cm more than the width what are the length and width of the rectangle?
length 14cm, width 2cm This is worked out by finding the following equations: perimeter = 16 x width length = width + 12 Then working out 16 x width = 2 x (width + 12) + 2 x width -> 14 x width = 2 x (width + 12) -> 14 x width = 2 x width + 24 -> 12 x width = 24 -> width = 2cm Since lendth = width + 12, length = 14cm
What are the dimensions of a table if the perimeter is 36 and the length is 5 times the width?
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
How do you work out find out the area when the length is twice the width?
length*width = 2*width*width i.e square the width and multiply by 2
The length of a rectangle is 3 inches more than its width and its perimeter is 22 inches Find the width of the rectangle?
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
The area of a rectangular patio is 900ft2 The patio's length is twice its width Find the dimensions of the patio?
AREA = LENGTH x WIDTH LENGTH = 2 X WIDTH AREA = 2 x WIDTH X WIDTH = 900 900/2 = WIDTH X WIDTH 450 = WIDTH X WIDTH = WIDTH SQUARED WIDTH = SQUARE ROOT (450) = 21.21 FEET LENGTH = 42.42 FEET
Does a line have width?
no it does not have a width
What is the width of Tennessee?
What is the width of Tennessee
What are the Nissan 240sx production numbers?
{| ! width="150" | 1989: | 68,118 ! width="150" | 1990: | 60,582 ! width="150" | 1991: | 34,534 ! width="150" | 1992: | 27,033 ! width="150" | 1993: | 21,471 ! width="150" | 1994: | 1,391 ! width="150" | 1995: | 25,114 ! width="150" | 1996: | 7,334 ! width="150" | 1997: | 3,655 ! width="150" | 1998: | 2,178 ! width="150" | Total: | 251,410 |}
What are the dimensions of a rectangle with length 5 in longer than its width which has 1 inside squares cut from the corners and the flaps folded up to form an open box of volume 500 cu in?
It is 22 in by 27 in. ------------------------------------------- How it is solved: The rectangle is 5 in longer than its width, so the dimensions can be given in terms of its width: Its dimensions are width by (width+5) In removing 1 inch squares from the corners, he flaps are going to be (width-2) and (width+5-2) = (width-3) long. Thus the box formed will have volume: volume = (width - 2) in × (width + 3) in × 1 in → volume = width² + width - 6 in³ But we are told this is 500 in³; thus: width² + width - 6 in³ = 500 in³ → width ² + width - 506 = 0 → (width + 23)(width - 22) = 0 → width = -23 or 22 As a length cannot be negative, the width must be 22 in which means the original rectangle is 22 in by 22+5 in = 27 in
