The short answer: they are identical: 50VA (through a resistive load) = 50Watts
The long answer:
Power can be divided into real power and reactive power. Real power is used to do real work. reactive power is stored and released in reactive elements (capacitors and reactors). A purely resistor is hard to get, having absolutely no reactance or capacitance. Because of this, watts defines the amount of real power available to do work; volt-amps defines the maximum current drawn at a specified voltage.
Ampere-hours is a battery hold-up time rating. Volts is a voltage rating. The two are not related, so the question cannot be answered as asked.
The average deep freezer or chest freezer uses about 130 watts. There are some energy saver models that might use less wattage.
In order to determine this, it will be necessary to find which resistor 'maxes out' at the lowest voltage. This can be found using the equation Vi=sqrt (Pi*Ri) for each resistor, where Pi is the power rating of resistor i and Ri is the value of resistor i. Once this is found, the power dissipation of each other resistor can be found using the equation Pi=(Vl^2)/Ri, where Vl is the voltage that maxes out the resistor which maxes out at the lowest voltage, and Ri is the resistance of each resistor. The equivalent power rating would then be the sum of the power dissipated across each resistor.
It depends on (1) its voltage rating, and (2) whether it is single phase or three phase. And the symbol for kilovolt ampere is kV.A -not 'kva'.
The rating is about 1500W. This is for both the input and the output. Output voltage is usually 2,000 volts. Divide watts by input volts to get input current. And divide watts by output voltage to get output current. -Joe
The 1N4007 is a diode with forward current rating of 1 ampere, and a reverse voltage rating of 1,000 volts.
Ampere-hours is a battery hold-up time rating. Volts is a voltage rating. The two are not related, so the question cannot be answered as asked.
To answer this question a voltage and HP must be stated.
Wattage or power rating of a product can be calculated by multiplying voltage rating and current rating. (Power = Voltage x Current). e.g. if device is working at 12V and 2A is the current rating. It is 24Watt. Since Voltage = Current x Resistance , for a resistive load power can also be calculated by Power = Current x Current x Resistance = I^2 x R = I square R
Current depends on the Wattage and the voltage rating of the device.
ITS NOT PRACTICAL BUT FOR THE SAKE OF SOLUTION HERE'S HOW: 1. KNOW WHAT IS THE VOLTAGE RATING OF CAR HEAD LAMP = 12 OR 24 VOLTS DC? 2. KNOW THE WATTAGE RATING OF CAR HEAD LAMP = SAY 100 WATTS 3. KNOW WHAT IS YOUR RESIDENTIAL SYSTEM VOLTAGE = 110VAC OR 220VAC? 4. PURCHASE AN AC TO DC CONVERTER - SELECTABLE 110VAC OR 220VAC INPUT VOLTAGE AND SELECTABLE 12VDC AND 24VDC OUTPUT VOLTAGE WITH A MINIMUM OF 10 AMPERE RATING.
The average deep freezer or chest freezer uses about 130 watts. There are some energy saver models that might use less wattage.
You cannot answer this question without knowing the rated secondary voltage. Once you know this, divided the voltage into the volt ampere rating.
Wattage = voltage x amperage. Every appliance in North America is built to work at 120 V, so you have the voltage. The amperage rating is probably written in the microwaves manual if the wattage is not. Remember the amperage you put on a circuit can't be more that 80% of what the wiring is rated for in the branch circuit.
Divide its power rating by its voltage rating. These ratings are found on its nameplate. For example, a 3-kW kettle rated at 230 V will draw a current of approx. 13 A.
Divide the wattage rating on the tag by the voltage it uses and that will give you the amperage.
Electric lamps have a wattage rating, but also have voltage ratings. Additionally, there are different socket styles for lamps, too.