It depends on (1) its voltage rating, and (2) whether it is single phase or three phase. And the symbol for kilovolt ampere is kV.A -not 'kva'.
According to 2011 nfpa 70 nec Motor conductors are sized with the flc- full load current or the nameplate rating fla- full load amperes
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
This is the current flowing in the primary circuit when full-load current flows in the secondary circuit.
All transformers, single phase or three phase have a "no-load current" rating. That is simply the nameplate rating of the Xformer in VA, (volt-amps) or KVA (1000Volt-amps) for larger Xformers. Simply divide the nameplate rating in VA or KVA by the supply voltage and you'll get the Xformers potential maximum output in ampheres.
It is the rated maximum current that can be taken from the transformer. This is equal to the VA rating divided by the output voltage. So a 6 kVA 240 v transformer would have a maximum current rating of 6000/240 or 25 amps.
A fuse rating is normally the 120% of the rated full load current. So, 4 amps times 120% is (4x120%) = 4.8amps
According to 2011 nfpa 70 nec Motor conductors are sized with the flc- full load current or the nameplate rating fla- full load amperes
2 to 5% of full load current
Generally we use CBCT for earth fault/earth leakage relay tripping. Since the CBCT is going to provide on neutral side, first we have to find the full load current. If the full load current is 500A we have to use 100A/5A (ie 1/5th of full load current) CBCT. arunarafa@gmail.com
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
This is the current flowing in the primary circuit when full-load current flows in the secondary circuit.
All transformers, single phase or three phase have a "no-load current" rating. That is simply the nameplate rating of the Xformer in VA, (volt-amps) or KVA (1000Volt-amps) for larger Xformers. Simply divide the nameplate rating in VA or KVA by the supply voltage and you'll get the Xformers potential maximum output in ampheres.
twice the full-load current. code 430.83(c)
The starting current of any electrical equipment which is 6 times more than that of the full load current. ex: full load current = 5 A the starting current will be 5*6 = 30 A.
The supply won't have to work as hard. It is perfectly acceptable, for example, to use a 1A, 12v supply to supply a 12v, .5A load. The current rating indicates the ability of the supply to dissipate heat caused by the current flowing. If the load current is above the power supply current rating, the power supply will overheat.
It is the rated maximum current that can be taken from the transformer. This is equal to the VA rating divided by the output voltage. So a 6 kVA 240 v transformer would have a maximum current rating of 6000/240 or 25 amps.
is it primary current ?