It is the rated maximum current that can be taken from the transformer. This is equal to the VA rating divided by the output voltage.
So a 6 kVA 240 v transformer would have a maximum current rating of 6000/240 or 25 amps.
Assuming single phase voltage 220 Volts AC, the maximum current would be approximately 25 amps.
Divide the VA by the voltage. But this transformer is probably a 3-phase one, maybe working on a 11,000 volt system, and in this case the live-to-neutral voltage is 6351 v and each phase supplies 3333 kVA. In this case the current supplied is 3,333,333 / 6351 or 525 amps on each phase. This is a common type of transformer in electricity supply.Another AnswerAssuming you are talking about the secondary line current of a three-phase transformer, you simply divide the rated apparent power of the transformer by (1.732 x rated secondary line voltage).Don't confuse line currents with phase currents. Line currents travel in the lines that connect the transformer with the load, whereas phase currents circulate within the windings.For example, let's assume you have a 10 MVA primary distribution transformer, with a rated secondary line voltage of 11 kV. The full load current would be:secondary line current = 10 000 000 / (1.732 x 11 000) = 525 A
It depends on (1) its voltage rating, and (2) whether it is single phase or three phase. And the symbol for kilovolt ampere is kV.A -not 'kva'.
Percentage reactance of a transformer (or in general, a circuit) is the percentage of phase voltage drop when full load current flows through it, i.e %X=(IX/V)*100. Now Short Circuit Current is V/X So short Circuit current is I*(100/%X).
No load current depends on the design of the transformer, and what voltage it is energized at. It will typically be below 1% of full load, and can be significantly below 1% for utility sized transformers.
..the questions does not say wether the 30kVA transformer is 3 phase transformer or single phase transformer..but it is implying that a single phase welding load at 16A per phase is to be connect to it, it is assumed then that the transformer is 3 phase transformer..we assume load is rated 240V.. ..though not much details is given about the transformer voltage specs. but if is rated 3 phase 415/240V, the approx full load current per phase is given by 30KVAx1.3912=41.736A.. ..but if the transformer was rated single phase 240V say, the approx full load current FLC=30000/240V gives 125ampers.. ..if you further devide the FLC by the intended load current.. ..Recommended no of welders per for a 3 phase 415V transformer and assuming single welding sets =41.736/16=2.6..so you can connect max two welding sets to this transformer per phase,..max 6 weld sets can connect at an approx load factor of 76%.. ..for the single phase transformer, FLC/16=125/16, gives 7.8 but is also recommended not to connect more than 6 welding sets to such transformer for the same reasons..
Assuming single phase voltage 220 Volts AC, the maximum current would be approximately 25 amps.
A load test on a transformer is done to make sure it stays within its designed temperature range while on full load.
is it primary current ?
Divide the VA by the voltage. But this transformer is probably a 3-phase one, maybe working on a 11,000 volt system, and in this case the live-to-neutral voltage is 6351 v and each phase supplies 3333 kVA. In this case the current supplied is 3,333,333 / 6351 or 525 amps on each phase. This is a common type of transformer in electricity supply.Another AnswerAssuming you are talking about the secondary line current of a three-phase transformer, you simply divide the rated apparent power of the transformer by (1.732 x rated secondary line voltage).Don't confuse line currents with phase currents. Line currents travel in the lines that connect the transformer with the load, whereas phase currents circulate within the windings.For example, let's assume you have a 10 MVA primary distribution transformer, with a rated secondary line voltage of 11 kV. The full load current would be:secondary line current = 10 000 000 / (1.732 x 11 000) = 525 A
2 to 5% of full load current
First find the ratio of the transformer. 6600/220 volts. Second find the secondary current, I = W/E, 99000/220. Third divide the secondary current by the transformer ratio. The answer will be the primary current. To check your answer (W (or VA) = V x A) multiply the primary current times the primary voltage and the secondary current times the secondary voltage and they should both equal the transformer's kVA.
zero volatge regulation means the terminal volatge of transformer at full load on a given power factor become equal to the rated teriminal volatge of transformer , it happens only for leading power factor in transformer
CT=========current transformer PT=========potential transformer these are the instrumental transformers.
A current transformer has to have the same ratio as the meter that it drives. Full scale deflection on the meter is 5 amps which equals the maximum allowed current on the phase that it is reading. A different ratio on the CT to meter would show an erroneous reading on the meter depending on the ratio of the connected CT. To keep costs down the meter is common to all three phases and is read by connecting the meter to the phase CT through a three position switch.
It depends on (1) its voltage rating, and (2) whether it is single phase or three phase. And the symbol for kilovolt ampere is kV.A -not 'kva'.
Percentage reactance of a transformer (or in general, a circuit) is the percentage of phase voltage drop when full load current flows through it, i.e %X=(IX/V)*100. Now Short Circuit Current is V/X So short Circuit current is I*(100/%X).