What is final velocity?
Final velocity is chronologically the last velocity.
Final velocity = (Initial velocity) + (time)(acceleration)
Well, (final velocity) = (initial velocity) + (acceleration x time)
When calculating acceleration to find the change in velocity you subtract the what velocity from the final velocity?
You subtract the initial velocity from the final velocity and divide by the time interval.
The final velocity is (the initial velocity) plus (the acceleration multiplied by the time).
Final velocity v = u + at
What is the formula for calculating final velocity when you know the initial speed and the acceleration?
the formula for finding acceleration is final velocity, minus initial velocity, all over time. So if you have the acceleration and initial speed, which is equal to the initial velocity, you must also have time in order to find the final velocity. Once you have the time, you multiply it by the acceleration. That product gives you the difference of the final velocity and initial velocity, so then you just add the initial velocity to… Read More
This can't be done with just final velocity and time. You need to know the acceleration. If you do know the acceleration, multiply it by the time, and subtract that from the final velocity.
Final velocity is the your last velocity traveled. Example if you travel 50m/s your final velocity is 50m/s because its the last velocity traveled, 0m/s is the initial velocity. Its not your total velocity because if u start running at 5m/s then accelerated 25m/s, your final velocity is NOT 30m/s. It is 25m/s. Also, your velocity change is 20m/s(25-5).
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
Final velocity = Initial velocity +(acceleration * time)
If you know the initial and final velocity you can determine the acceleration (Velocity final- Velocity initial)/time = acceleration This can also be seen by integrating the acceleration. In this case lets assume acceleration is constant, then: acceleration=C Integration from time=initial to time=final gives C*(time final-time initial)=velocity final-velocity initial This integration scheme can also work if acceleration is not constant. In this case you must know how acceleration or velocity changes with time.
"Initial" means the velocity it had when you started looking at it. "Final" means the velocity it had when you were finished looking at it.
zero because the initial and final velocity is constant . so,difference bet. final velocity and initial velocity is zero
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
final velocity, or terminal velocity.
Distance = |(v2 - u2)/(2a)| where initial velocity = u final velocity = v accelaration = s
If you have constant acceleration, then you can't have constant velocity. (Unless the acceleration is constantly zero.) Final velocity = [initial velocity] + [ (acceleration) x (time) ]
What would be true of the values for initial velocity and final velocity if the acceleration were zero?
A change in velocity can be effected only by acceleration. Therefore, if the acceleration is zero, there is no change, so final velocity equals initial velocity.
There are a number of different formulas for final velocity. Each one describes the relationship between final velocity and other kinematic quantities, such as initial velocity, initial and final position, acceleration, and time. Depending on what information you have, you would select the most appropriate and useful formula.
Vf= Final Velocity Vo= Original Velocity a= Acceleration t= Time Vf=Vo+a(t)
If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time
If an object is accelerating what equation relates the acceleration of that object the initial velocity and the final velocity and time?
Vf = Vi + at Where Vf = final velocity Vi = initial velocity a = acceleration t = time
Vf = Vi + a * t Vf = final velocity Vi = initial velocity * = multiply t = change in time a = accelaration
Perhaps you mean Terminal Velocity, as in a parachute fall? This is the maximum speed reached in the fall. Final velocity will be zero, assuming you arrive on the ground.
Vf= Final Velocity Vo= Original Velocity a= Acceleration t= Time Vf=Vo+a(t) that the one that i only know.....
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
What will be the final velocity if the acceleration of 10 meters per second squared is sustained for 7 seconds?
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
Assuming initial velocity is zero and this is in a vaccum, the final velocity would be gXt where g is the accleartion due to gravity which is 9.8 m/s^2. Therefore, the final velocity would be 98 m/s.
the final velocity assuming that the mass is falling and that air resistance can be ignored but it is acceleration not mass that is important (can be gravity) final velocity is = ( (starting velocity)2 x 2 x acceleration x height )0.5
Initial velocity is the velocity an object begins with Final velocity is the velocity at which the object ends up in Say a car is travelling at 13 m/s and then crashes into a wall stopping it it's intitial velocity was 13 m/s and it's final velocity is at 0 m/s or Say a car starts off at 5 m/s but then accelerates from 5 m/s to 10 m/s. It's inital velocity would be 5… Read More
final velocity v of an object which starts with velocity u and then ... vector w, then the velocity of object A relative to object B is defined as the difference
What is the final velocity of an object that starts at 45 mph and accelerates at a rate of -10 mphsec for 3 seconds?
the final velocity = initial velocity + acceleration x time; since acceleration is negative final velocity = 45 - 10x3 = 45 -30 = 15 mph
Final Velocity- Initial Velocity Time
(Final Velocity - Initial Velocity) / Time
force and mass. acceleration=force divided by mass or the time, final velocity, and initial velocity. acceleration= final velocity minus initial velocity diveded by time
Let's take a simple example to illustrate the concept. A pitch is thrown by a pitcher. It starts at zero velocity (in his hand) and reaches a final velocity of 100 mph. Average velocity will be (100 + 0)/2 = 50 mph Obviously the maximum velocity is 50 X 2 = 100 mph However this is only true if the initial velocity (or the final velocity for a ball slowing down) is zero.
No, It is the average velocity.
Acceleration is an object's change in velocity divided by its change in time. So: acceleration=(final velocity - initial velocity)/(final time - initial time)
Ifv = Final velocity u = Initial velocity a = Acceleration and t = Time then, provided the measurement units are consistent, v = u + at Ifv = Final velocity u = Initial velocity a = Acceleration and t = Time then, provided the measurement units are consistent, v = u + at Ifv = Final velocity u = Initial velocity a = Acceleration and t = Time then, provided the measurement units are… Read More
It doesn't necessarily mean that the final velocity is always greater than the initial, if the initial velocity was at rest or 0 m/s then any form of movement would be greater. In cases where the final is smaller is like running into a wall or a decrease in acceleration.
There are two methods, it depends on what variables you have: 1. Subtract the initial velocity from the final velocity and divide that whole term by the time (Vf- Vi)/t = a 2. Square both the initial velocity and the final velocity and subtract the squared inital velocity from the squared final velocity and that answer by two times the distance (Vf^2 - Vi^2)/2d = a
yes it does. u can calculate the final velocity of the falling object with the following eqn: initial potential energy= final kinetic energy or mgh = 1/2mv2 where m=mass, h = height,v=final velocity
Yes, of course.
(acceleration X time) + beginning velocity = final speed
It's equal to the change in velocity (final velocity - initial velocity).
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope… Read More
you cannot. you need to know one or the other if you're doing a problem where someone is throwing something in the air, the final velocity is 0
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
What is the final velocity of an object that decreases in kinetic energy and increases in potential energy?
Its final velocity will be zero when it reaches maximum potential energy.
Use s=ut+0.5at^2 (^2 notation for squared) Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time) v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = Time Then calculate displacement (s) using s=0.5(u+v)t