Use the mechanics formula
Final velocity = initial velocity + acceleration * change in time
4m/s = 0 + (9.8 m/s²)t
t = 0.41s
distance = initial velocity * time + 1/2 accel * time²
= 1/2(9.8m/s²)(0.41s)²
= 0.82m
When a pendulum reaches its maximum elongation the velocity is zero and the acceleration is maximum
It falls down. When it reaches a hard bottom it is likely to bounce whereas if it hits water it will sink.
The faster something moves, the more air resistance is created. So as gravity pulls something faster, the air resistance increases as it's speed does, until the forces of air resistance and gravity are equal, making the object move at a steady pace.
(any unit of distance) divided by (any unit of time)2 is a unit of acceleration.The acceleration of gravity is usually expressed in meters/second2 or feet/second2 .
As water is cooled its density increases until it reaches about 4 C and then it decreases.
When THE FRICTION BETWEEN THE OBJECT AND THE ATMOSPHEREequals the force of gravity on a falling object the object reaches terminal velocity.
Yes
Fired ammunition from a firearm reaches a much higher initial velocity due to explosive propellant forces. In contrast, ammunition dropped from a high altitude reaches a terminal velocity where gravity pulling down is balanced by air resistance pushing up. The fired bullet maintains its higher velocity until slowed by air resistance and gravity, while dropped ammunition reaches a constant speed due to these opposing forces.
the greatest velocity a falling object reaches is terminal velocity
The force acting on a free falling body, neglecting air friction, is solely the force of gravity. This force causes the body to accelerate downward at a rate of 9.8 m/s^2 (or 32 ft/s^2) until it reaches terminal velocity or impacts the ground.
yes. If the forces acting on the a moving particle are in equilibrium, (e.g. when a spherical object reaches terminal velocity (neglecting increased air resistance as it gets closer to the ground)) then the particle will be moving at a velocity, that is not 0, yet the velocity will remain constant, and the body will not accelerate or decelerate in any direction, and thus the acceleration is 0.
On any planet with an atmosphere, gravity is counteracted by the force of air friction with the object that is falling. This is known as terminal velocity - the point at which the forces of air resistance and gravity balance.
The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.
The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
It will have both horizontal and vertical velocity...think about it, if you were said bird flying through the sky at say 35 mph, and you dropped a rock then the rock would fall, but it would still be moving forward and it would fall the same way a baseball falls after it reaches the top of the throw.
the greatest velocity a falling object reaches is terminal velocity
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.