When a pendulum reaches its maximum elongation the velocity is zero and the acceleration is maximum
Perhaps you mean terminal velocity. This is the maximum velocity reached by an object falling to the ground when the acceleration due to gravity is matched by the drag resistance of the air through which it is falling.
No. Terminal velocity is a particular kind of velocity and friction is a particular kind of force. The terminal velocity of a falling object is the maximum velocity it can have because air resistance prevents it from going any faster. And air resistance is a type of friction. So terminal velocity is due to a type of friction.
Assuming that Earth is an inertial frame, and that the refraction index of air=1, the maximum possible velocity on Earth is the speed of the light, which equals 299 792 458 m/s. Albert Einstein postulated this back in early 1900's.
The maximum speed of any object is hardly equal to speed of light which is 3*10^8 approximately.
0 velocity
The instantaneous acceleration of the particle is equal to 0 when the velocity of the particle is at a maximum or minimum. This occurs at the points on the graph where the slope of the velocity-time graph is horizontal or the velocity reaches a peak or trough.
The acceleration at instantaneous maximum velocity is zero, as the velocity is not changing at that moment.
When acceleration is 0, it means there is no change in velocity. At a maximum point, the velocity is either increasing or decreasing, but when it reaches that point, the acceleration is 0.
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.
The maximum velocity that a particle can reach in a cyclotron is limited by the speed of light, which is approximately 3 x 10^8 m/s in a vacuum. As particles in a cyclotron are accelerated closer to the speed of light, they experience relativistic effects that make further acceleration more difficult.
The velocity of a fluid particle at the center of a pipe in a fully developed flow is half of the maximum velocity in the pipe. This is known as the Hagen-Poiseuille flow profile for laminar flow.
the acceleration is equal to energy that release by the friction that came be electic that travel form somewhere.It proves that maximum acceleration rate.The easy explainationof that is Energy and Velocity are equal to maximum of acceleration
The minimum acceleration for a particle in simple harmonic motion obeying x = Acos(2t) is when the particle is at its maximum displacement, which corresponds to the amplitude A in the equation. At these points, the acceleration is zero since the restoring force is at its maximum and velocity is changing direction.
Yes, a particle can have a maximum speed without acceleration if it is moving at a constant velocity. In this case, its speed remains constant and there is no change in velocity over time, resulting in zero acceleration.
Acceleration is maximum at the extreme points of a simple pendulum because that is where the velocity is zero and the direction of acceleration changes from negative to positive (or vice versa). This change in acceleration direction leads to a maximum magnitude of acceleration at the extreme points.
I'm trying to give you a simple example. Which hope will be able to make you understand that thing. We read physics in our language. So I can make some mistakes to write that in English... But I hope I won't be mistaken. By the way here it is... Suppose, There is a simple oscillator what is moving under the angles of 4 degrees. When it is in his height position then we know that it stops for a moment and then comes back to the equilibrium position. So in the height position it's velocity is 0 m/s. (cause it stops.) Suppose it's 1st velocity or the velocity in the equilibrium position is "v" and in that position the last velocity is 0. so we can calculate it's acceleration like that a = (last velocity-1st velocity)/time so a = (0-u)/t = - u/t, what is the maximum acceleration of a this body, (-) sign means the acceleration is gonna go down. But when it is coming back to the equilibrium position, it's velocity goes up.. And in the equilibrium position it's velocity is maximum. Then the velocity decreases again. so in the equilibrium position the velocity is maximum, in the equilibrium position which is "v". so it's acceleration will be a= v-v/t = 0/t = 0, that means the acceleration is zero when the velocity is maximum... That means the acceleration of a body can be zero when the velocity is maximum and the velocity can be zero when the acceleration is maximum. [Note: Always remember, to start to calculate from the equilibrium position. Because the oscillation starts from the equilibrium position. And what I said is the most simple statement. It can also be described by the equations of the a simple harmonic oscillations] - by JAS