Cyclotron pulse multiplied with the maximum radius
Maximum
Terminal Velocity
maximum torque
amplitude
The maximum velocity of a falling person is about 200 miles per hour; at that point the air resistance does not allow further acceleration.
When a pendulum reaches its maximum elongation the velocity is zero and the acceleration is maximum
Maximum
0 velocity
Velocity is maximum at mean position for particle performing simple harmonic motion. Another feature that is maximum at this position is kinetic energy.
The final energy attained by a deuteron undergoing cyclotron acceleration depends on the design of the cyclotron. In some machines the final energy may be as low as 3MeV whilst in others, 25MeV. Above 25MeV reletavistic effects kick-in and the cyclotron needs to be more sophisticated in its design. It does depend on the cyclotron. Theres actually an equation for that. It takes into account the maximum radius of the orbit of the particles and the wavelength of the accelerating voltage. So for a given cyclotron with exactly specified values for radius and wavelength, the maximum kinetic energy of a particle depends on its rest energy and, hence, its rest mass. But heres an easy way to figure it out: If a given cyclotron can accelerate protons to an energy of say, 2 MeV, then deuterons can be accelerated to 4 MeV. Multiply by a factor of 2.
The maximum displacement upwards is given by the equation y=-vxv/2g. At the peak, the value of velocity is said to be v=0.
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.
Maximum Velocity - 2003 is rated/received certificates of: USA:PG-13
Terminal Velocity
maximum torque
At the point where the velocity is the maximum
amplitude