One Nitrogen atom = one -NH2. H3C-CH2-CH2-NH2. 1-amino-propane.
No.
Reaction: CH3C(=O)CH3 + NH2NHC(=O)NH2 --> (CH3)2C=NNHC(=O)NH2 1) N from NH2 acts as the nucleophile, attacks the carbonyl group and changes into a tetrahedral intermediate. Positive charge on NH2, negative charge on oxygen. (CH3)2(O-C)--(NH2)+NHC(=O)NH2 2) oxygen takes the hydrogen from nitrogen through rearrangement because it is more electronegative. (CH3)2(HOC)--(NH)NHC(=O)NH2 3) Acid protonates the alcohol once more to make it a better leaving group. (CH3)2(H2O+C)--(NH)NHC(=O)NH2 4) Nitrogen from NH2 donates its electrons to generate a double bond, bumping off the water molecule and leaving a positive charge on nitrogen. (CH3)2C=NH+NHC(=O)NH2 5) Water pulls off the hydrogen that was still attached to the nitrogen, thus generating the condensation product between acetone and semicarbazide. (CH3)2C=NNHC(=O)NH2
The abbreviation for Acetate is CH3COOH. This is an organic acid.
Ch3-c(=o)-nh2
O O O CH3-C-OH+HCl--------> CH3-C-Cl+NH3 ---------> CH3-C-NH2 O CH3-C-NH2+Br2+KOH -----------> H3C-NH2+KBr+K2CO3+H2O
One Nitrogen atom = one -NH2. H3C-CH2-CH2-NH2. 1-amino-propane.
ethanol
H3C is a part of the larger compound H3C-CH2-O-CH3, which is ethyl methyl ether, also known as methoxyethane.
2-butylhexanoic acid
2-propylpentanoic acid
No.
esters
H3C is a part of the larger compound H3C-CH2-O-CH3, which is ethyl methyl ether, also known as methoxyethane.
Reaction: CH3C(=O)CH3 + NH2NHC(=O)NH2 --> (CH3)2C=NNHC(=O)NH2 1) N from NH2 acts as the nucleophile, attacks the carbonyl group and changes into a tetrahedral intermediate. Positive charge on NH2, negative charge on oxygen. (CH3)2(O-C)--(NH2)+NHC(=O)NH2 2) oxygen takes the hydrogen from nitrogen through rearrangement because it is more electronegative. (CH3)2(HOC)--(NH)NHC(=O)NH2 3) Acid protonates the alcohol once more to make it a better leaving group. (CH3)2(H2O+C)--(NH)NHC(=O)NH2 4) Nitrogen from NH2 donates its electrons to generate a double bond, bumping off the water molecule and leaving a positive charge on nitrogen. (CH3)2C=NH+NHC(=O)NH2 5) Water pulls off the hydrogen that was still attached to the nitrogen, thus generating the condensation product between acetone and semicarbazide. (CH3)2C=NNHC(=O)NH2
(CH3COOC2H3)nStructural:(H3C-(C=O)-O-(CH)=CH2)n
H3c-c(=o)(-och3)