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T = 28.9°C + 1.7°C/hr × 3 hr - 0.5°C/hr × 4 hr

= 28.9°C + 5.1°C - 2 °C

= 32°C

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Q: What is its final temperature if a glass jar of water initially at 28.9C but the water warmed by 1.7C each of 3 hours in the sun and lost 0.5C during each of the 4 hours it sat in shade?
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