reactants are favored over products in the reaction
A rate constant
Q indicates wether or not a reaction will occur when the value of Q is compared to the equilibrium constant K if Q is larger than K the reaction will occur from product to reactant (decomposition) if Q is smaller than K the reaction will occur from reactant to product
The reaction is:Ag+ + (NO3)- + K + I- = AgI(s) + (NO3)- + K
MeOH + K ---->> K+ -O-CH2-CH3
reactants are favored over products in the reaction
reactants are favored over products in the reaction
K-2so
Keq = products/reactions
I suspect it could be " k eq 1" , or "k =1".
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2
In the equilibrium system: aA + bB <=> cC + dD [A]a x [B]b K = ___________ [C]c x [D]d Where A, B, C and D are gases or solutions. Pure liquids and solids are not included in the equilibrium constant expression.
Equal to one another. K= k1/k-1 where k1 is the forward reaction, k-1 is the backwards reaction and K is the equilibrium constant.
NO!!! A large Equilibrium Constant means that nearly all the reactants have been used up to reach the equilibrium. Conversely a small K(eq) indicates that equilibrium is reached when very little of the reactants have been used.
The CV value is the flow rate required to generate 1 psid of pressure loss through the valve. Since pressure drop follows a basic square law the relationship between Cv, flow and pressure loss is as follows: DP = k x Flow^2 eq 1 Where k is a constant that represents the flow shape in the wide open condition. Since Cv is the flow rate at 1 psi of pressure loss then it follows that DP = k x Cv^2 = 1 eq 2 solving for k from eq 2 yields k = 1/Cv^2 eq 3 substituting eq 3 into eq 1 yields DP = (Flow/Cv)^2 Now you have an equation that will tell you the pressure and flow relationship for that particular valve with a particular fully open Cv value. In short, the higher the Cv value the more flow the valve will allow for the same pressure loss or the less pressure loss for the same flow. Good luck
MgSO4 + KOH --> MgOH + K2SO4 And I want to think that MgOH is a solid
If Q > K, the reaction will move towards the reactants If Q < K, the reaction will move towards the products