Wave frequency
0 degrees F equals -17.8C
use a kinematic equation or F = MA
The period (T) of a circle is represented by the equation: T=1/F, where F is the frequency.
Wavelength = (wave speed) divided by (period)
Solve f(x) =0 or y = 0 (depending on how the equation is given).
If the equation is of the form y = f(x) where f is some function of the variable x, then The initial value is found by evaluation f(0): that is, the value of f(x) when x = 0. The rate of change is the derivative of f(x) with respect to x, written as f'(x). That is the limit (if it exists), as dx tends to 0, of [f(x+dx) - f(x)]/dx. In the simple case, where f(x) is a linear equation of the form y = mx + c, then f(0) = c and f'(x) = m
It is the value of the equation y = f(x) when x = 0.
An equation may or may not have a derivative. The derivative of a function f(x), is usually defined as the limit as h tends to 0, of [f(x+h) - f(x)]/h
0. Differentiation of a constant gives f'(x)=0.
The conversion equation is F = (9/5)C + 32. To convert 0 deg. C to F, replace C with 0, and the answer is 32 deg. F, or the freezing point of water.
When we solve an equation in mathematics we say that we find its root. Let f(x) = 0 be an equation. A root of the equation is a value k such that f(k) = 0. If f(x) is a polynomial, then f(x) = 0 is a polynomial equation. By the Factor Theorem, k is a root of this equation if and only if (x - k) is a factor of f(x). If (x - k) is a factor of f(x), then k is a simple root. If (x - k)^2 is a factor of f(x), then k is a double root. If (x - k)^3 is a factor of f(x), then k is a triple root, and so on. Thus, we can say that a root of order n, where n = 2 or n > 2, is a multiple (or repeated) root.
To find the ordered pairs in any equation, just plug in any number for x and solve for y. If your equation is meant to be y=1+5x, then if x=0 then y=1+5*0, y=1 so the first ordered pair would be (0,1) If your equation is meant to be y=(1/5)x, then if x=0 then y=(1/5)*0, y=0, so the first ordered pair would be (0,0)
Put f(x) = 0 and solve for x.
You need it in the form f(x)= ... (whatever your equation happens to be). i.e get the equation in the form y=... Then swap the 'y' for 'f(x)'. Simple.
The substitute of F in the equation F times 2 X times 3 X would be 0. This is taught in math.
A Laplace transform is a mathematical operator that is used to solve differential equations. This operator is also used to transform waveform functions from the time domain to the frequency domain and can simplify the study of such functions. For continuous functions, f(t), the Laplace transform, F(s), is defined as the Integral from 0 to infinity of f(t)*e-stdt. When this definition is used it can be shown that the Laplace transform, Fn(s) of the nth derivative of a function, fn(t), is given by the following generic formula:Fn(s)=snF(s) - sn-1f0(0) - sn-2f1(0) - sn-3f2(0) - sn-4f3(0) - sn-5f4(0). . . . . - sn-nfn-1(0)Thus, by taking the Laplace transform of an entire differential equation you can eliminate the derivatives of functions with respect to t in the equation replacing them with a Laplace transform operator, and simple initial condition constants, fn(0), times a new variable s raised to some power. In this manner the differential equation is transformed into an algebraic equation with an F(s) term. After solving this new algebraic equation for F(s) you can take the inverse Laplace transform of the entire equation. Since the inverse Laplace transform of F(s) is f(t) you are left with the solution to the original differential equation.